Best Answer

(tan x - sin x)/(tan x sin x) = (tan x sin x)/(tan x + sin x)

[sin x/cos x) - sin x]/[(sin x/cos x)sin x] =? [(sin x/cos x)sin x]/[sin x/cos x) + sin x]

[(sin x - sin x cos x)/cos x]/(sin2 x/cos x) =? (sin2 x/cos x)/[(sin x + sin x cos x)/cos x)

(sin x - sin x cos x)/sin2 x =? sin2 x/(sin x + sin x cos x)

[sin x(1 - cos x)]/sin2 x =? sin2 x/[sin x(1 + cos x)

(1 - cos x)/sin x =? sin x/(1 + cos x)

(1 - cos x)/sin x =? [(sin x)(1 - cos x)]/[(1 + cos x)(1 - cos x)]

(1 - cos x)/sin x =? [(sin x)(1 - cos x)]/[1 - cos2 x)

(1 - cos x)/sin x =? [(sin x)(1 - cos x)]/[1 - (1 - sin2 x)]

(1 - cos x)/sin x =? [(sin x)(1 - cos x)]/sin2 x

(1 - cos x)/sin x = (1 - cos x)/sin x True

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Q: Prove each Indentity tanx mins sinx divided by tanxsinx equals tanxsinx divided by tanx plus sinx?

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You can't prove it, because it's usually not true.The only time it's true is when x=0 .

It is extremely difficult to prove things which are not true.

that cannot be proved because it is not necessarily true.

11

ask yourself if anything can go into 57 or 111 (divided)

Related questions

Cannot prove that 2 divided by 10 equals 2 because it is not true.

Because there is no way to define the divisors, the equations cannot be evaluated.

What divided by 7 equals 8? In other words, you have an unknown number (X), and then if you divide that X by 7 you get 8. Then what is that X? The equation to calculate what divided by 7 equals 8 is as follows: X/7 = 8 Where X is the answer. When we solve the equation by multiplying each side by 7, you get get: X = 56 Therefore, the answer to what divided by 7 equals 8 is 56.

You can't it equals 2. You can't it equals 2.

No you can not prove that 9 +10 = 21.

prove:E=mc2

No, but there is a way to prove that zero equals one.

Using faulty logic.

It is not possible to prove it because it is not true!

a0=(a-1\a-1)=a\a=1

You cannot prove it since it is axiomatic. You can get consistent theories (matrix algebra, for example) where ab is not ba.

Using a calculator

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