answersLogoWhite

0


Best Answer

Assume that f:S->T is invertible with inverse g:T->S, then by definition of invertible mappings f*g=i(S) and g*f=i(T), which defines f as the inverse of g. So g is invertible.

User Avatar

Wiki User

10y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Prove that the inverse of an invertible mapping is invertible?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

If matrix a is invertible and a b is invertible and a 2b a 3b and a 4b are all invertible how can you prove that a 5b is also invertible?

What is "a 3b"? Is it a3b? or a+3b? 3ab? I think "a3b" is the following: A is an invertible matrix as is B, we also have that the matrices AB, A2B, A3B and A4B are all invertible, prove A5B is invertible. The problem is the sum of invertible matrices may not be invertible. Consider using the characteristic poly?


Is the invertible to be one to one function?

Yes, a function needs to be one-to-one in order to have an inverse.


What are applications of determinants?

If you think of a matrix as a mapping of one vector to another, by either rotation or stretching, then the determinant tells you what size one unit volume is mapped to. This also can tell you if a matrix has an inverse as at least one dimension in a non-invertible matrix will be mapped to zero, making the determinant zero.


Can an invertible function have more than one x-intercept?

No. If the function has more than one x-intercept then there are more than one values of x for which y = 0. This means that, for the inverse function, y = 0 should be mapped onto more than one x values. That is, the inverse function would be many-to-one. But a function cannot be many-to-one. So the "inverse" is not a function. And tat means the original function is not invertible.


What is the answer of opposite or inverse?

Two operators are opposites or inverses if their combined mapping is the identity mapping. Less technically, one mapping must reverse the effect of the other. There are problems, though, when dealing with even fairly common functions. Squaring is a function from the real numbers to the non-negative real numbers, but there is not a single inverse operation. [+sqrt and -sqrt are the two inverse functions over the range.]


What is the range of the inverse of relation (1 7) (2 -4) (5 6) (2 8)?

The original relationship is one-to-many. It is therefore not an invertible relationship.


What is an input or output relation that has exactly one output for each input?

A one-to-one function, a.k.a. an injective function.


Is the inverse of the function y x2 still a function?

Y = 1/X2 ==============Can it pass the line test? * * * * * That is not the inverse, but the reciprocal. Not the same thing! The inverse is y = sqrt(x). Onless the range is resticted, the mapping is one-to-many and so not a function.


What is a projection in mathematics?

Generally speaking, in mathematics, a projection is a mapping of a set (or of a mathematical structure) which is idempotent, which means that a projection is equal to its composition with itself. A projection may also refer to a mapping which has a left inverse.


If F -1(x) is the inverse of F(x) which statements must be true?

"F(x) is a bijective mapping" nust be true.


Is a to power of 4 multiplied by b to power of 5 invertible?

Indeterminate. How? a4b5 is the expression instead of equality. Since we are not given the equality of two variables, there is no way to determine whether it's invertible or not. Otherwise, if you are referring "a" and "b" as invertible matrices, then yes it's invertible. This all depends on the details.


How do you prove the ideal bandpass filter theorem with an inverse Fourier transform?

this question on pic