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Pseudocode representation to determine the average of three numbers?
Wiki User
∙ 12y ago
#include <iostream>02using namespace std;
03
04int main()
05{
06 int sum = 0;
07 int average = 0;
08 int array[10] = {1,2,3,4,5,6,7,8,9,10};
09 for (int i = 0; i < 10; ++i)
10 sum+=array[i];
11 average = sum/10;
12 cout<<"Average:"<<average;
13}
Wiki User
∙ 12y ago
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Normally, at least two numbers are used to determine an average. If there is only one number, then the average is the number itself, so the answer is 48.
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