#include <iostream>02using namespace std;
03
04int main()
05{
06 int sum = 0;
07 int average = 0;
08 int array[10] = {1,2,3,4,5,6,7,8,9,10};
09 for (int i = 0; i < 10; ++i)
10 sum+=array[i];
11 average = sum/10;
12 cout<<"Average:"<<average;
13}
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To write pseudocode that accepts five numbers and displays their sum and average, you can follow these steps: Initialize a variable sum to 0. Loop five times to accept input for each number, adding each to sum. After the loop, calculate the average by dividing sum by 5. Display both the sum and the average. Here’s a simple representation: BEGIN sum = 0 FOR i FROM 1 TO 5 DO INPUT number sum = sum + number END FOR average = sum / 5 OUTPUT "Sum: ", sum OUTPUT "Average: ", average END
Standard form
Normally, at least two numbers are used to determine an average. If there is only one number, then the average is the number itself, so the answer is 48.
Certainly! Here's a simple pseudocode snippet that reads two numbers, multiplies them together, and prints out their product: 1. Read firstNumber 2. Read secondNumber 3. product = firstNumber * secondNumber 4. Print product In this pseudocode, we first read the two numbers, then multiply them to calculate the product, and finally print out the result.
Whole numbers are the best representation of students.