Details: Total possible Outcomes... (1,1), (1,2),(1,3),1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5,),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
Outcome with sum 6.... (1,5),(2,4),(3,3),(4,2),(5,1)
5 of 36. That's about 14% if you round up.
If they are normal dice, the probability is 0.
I apologize my question should have read what are the characteristics of a standard normal probability distribution? Thank you
On a single roll of a normal die the probability of getting a 7 is 0.
With a normal 6-sided die the probability would be 2/6, or 1/3.
With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.
No. Normal distribution is a continuous probability.
Even if I assume that you mean probability and not probility, the question cannot be answered since there is no information as to what is being rolled. For a normal tetrahedral die, the answer is 1.
Even if I assume that you mean probability and not probility, the question cannot be answered since there is no information as to what is being rolled. For a normal tetrahedral die, the answer is 1.
I t is necessary to assume thata single card is drawn,it is drawn at random,it is a normal deck of cards.If these assumptions are realised - and there is nothing in the question to suggest that they are - then the probability is 1/52.
Since the numbers (number of dots) on normal dice only go from 1 - 6, then I would think the probability of getting the number 100 is zero.
The experiment is undefined. On a single roll of eight or more normal dice the probability of getting a sum of 7 is 0.