I t is necessary to assume that
If these assumptions are realised - and there is nothing in the question to suggest that they are - then the probability is 1/52.
It is necessary to assume that
If these assumptions are realized - and there is nothing in the question to suggest that they are - then the probability is 1/52.
I t is necessary to assume that
a single card is drawn,
it is drawn at random,
it is a normal deck of cards.
If these assumptions are realised - and there is nothing in the question to suggest that they are - then the probability is 1/52.
I will have to say, that answer is correct but this is if you are leaving out the joker and usually, that is two more, so my answer and I agree with 1/52 but also include 1/54
If it is drawn at random, the probability is 1/52.
The probability of getting a diamond and a black seven is zero. Diamonds are red.
(1 in 52) or about 0.01923.
From a 52 card deck, probability is 1/52.
The probability of drawing a red spade is zero. There are no red spades in a standard deck.
Probability of drawing a seven of spades, from a 52 card deck, is 1/52.
If it is drawn at random, the probability is 1/52.
The probability of drawing the Four of Spades from a standard deck of 52 cards is 1 in 52, or about 0.01923.
The probability of getting a diamond and a black seven is zero. Diamonds are red.
Seven of Spades - film - was created in 1916.
There are 52 cards in a deck and 1 ace of spades. So the probability is 1/52 or unlikely.
0 chance
(1 in 52) or about 0.01923.
From a 52 card deck, probability is 1/52.
The probability of getting a particular suit (hearts, spades, diamonds, clubs) is 1 in 4. The probability of getting a card less than 8 (2, 3, 4, 5, 6, 7) is 6 in 13. The probability, then, of getting a particular suit less than 8 is (1 in 4) times (6 in 13) or 6 in 52 or 3 in 26.
The probability of dealing the Ace of Spades from a normal 52 card deck is 1 in 52. The probability of dealing the King of Spades next is 1 in 51. The probability of dealing the Queen of Spades next is 1 in 50.The probability of drawing those three cards in that order is the product of those probabilities, which is 1 in 132,600. This is the same as the number of permutations of N (52) things taken P (3) at a time, which is stated as N! - P! (52 * 51 * 50)If you did not care what order the cards were dealt in, but still wanted to know the probability of getting the Ace, King, and Queen of Spades, then you would be talking about the combinations of N (52) things taken P (3) at a time, which is stated as (N! - P!) / (N - P)! (52 * 51 * 50 / 3 / 2 / 1). The probability in this case is 1 in 22,100.
The probability of getting only one tails is (1/2)7. With seven permutations of which flip is the tails, this gives a probability of: P(six heads in seven flips) = 7*(1/2)7 = 7/128