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Ratio of in and ft

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Anonymous

15y ago
Updated: 8/17/2019

in:ft = 12:1

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Wiki User

15y ago

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If the areas of two similar decagons are 625 sq ft and 100 sq ft what is the ratio of the perimeters of the decagons?

If lengths are in the ratio a:b, then areas are in the ratio a2:b2 since area is length x length. If areas are in the ratio c:d, then lengths are in the ration sqrt(c):sqrt(d). Areas of decagons are 625sq ft and 100 sq ft, they are in the ratio of 625:100 = 25:4 (dividing through by 25 as ratios are usually given in the smallest terms). Thus their lengths are in the ratio of sqrt(25):sqrt(4) = 5:2 As perimeter is a length, the perimeters are in the ratio of 5:2.


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Convert one or the other so that they are the same units. 1 yd = 3 ft, so 4 yd = (4 yd)x(3 ft/yd) = 12 ft.Ratio 4 ft : 4 yd is the same as ratio 4 ft : 12 ft --> simplify to 1 ft : 3 ft --> 1:3You could convert feet to yards also, so that they are the same units. so 4 ft = (4 ft)/(3 ft/yd) = 4/3 yd.Ratio 4 ft : 4 yd is the same as ratio 4/3 yd : 4 yd --> simplify to 1/3 : 1 --> 1:3


If the areas of two similar decagons are 625 ft2 and 100 ft2 what is the ratio of the perimeters of the decagons?

The areas of two similar decagons are in the ratio of 625 ft² to 100 ft², which simplifies to 6.25:1. Since the ratio of the perimeters of similar shapes is the square root of the ratio of their areas, we take the square root of 6.25, which is 2.5. Therefore, the ratio of the perimeters of the decagons is 2.5:1.