The ratio of the length of the side of a right angle triangle must be 3,4,5
16,56,65
are not in that ratio.
No because the given dimensions do not comply with Pythagoras' theorem for a right angle triangle
If that '56' has units of 'degrees', then the vertex angle is 68 degrees.
Acute triangle - all of the angles are less than a right angle (90°).Scalene triangle - none of the sides or angles are congruent. It can be shown that if no two angles are the same, then no two sides are the same using the Law of Sines and Law of Cosines.
62 degrees
true
No because the given dimensions do not comply with Pythagoras' theorem for a right angle triangle
The triangle can be (56, 56, 68) or (56, 62, 62).
If you mean lengths of 33 by 56 by 65 then the given dimensions will form a right angle triangle.
The 3rd angle is: 180-94-56 = 30 degrees
If each base angle is 56°, then the vertex angle is 68°.If both base angles combined total 56°, then the vertex angle is 124°.
Assuming a right-angle triangle whose length is vertical, and the width is the base, then (14×8) ÷ 2 = 56 square units.
If that '56' has units of 'degrees', then the vertex angle is 68 degrees.
Acute triangle - all of the angles are less than a right angle (90°).Scalene triangle - none of the sides or angles are congruent. It can be shown that if no two angles are the same, then no two sides are the same using the Law of Sines and Law of Cosines.
56 degrees
62 degrees
Vertex angle = 180 - 2(62) = 56 degrees
true