No because the given dimensions do not comply with Pythagoras' theorem for a right angle triangle
Acute triangle - all of the angles are less than a right angle (90°).Scalene triangle - none of the sides or angles are congruent. It can be shown that if no two angles are the same, then no two sides are the same using the Law of Sines and Law of Cosines.
If that '56' has units of 'degrees', then the vertex angle is 68 degrees.
62 degrees
true
No because the given dimensions do not comply with Pythagoras' theorem for a right angle triangle
The triangle can be (56, 56, 68) or (56, 62, 62).
If you mean lengths of 33 by 56 by 65 then the given dimensions will form a right angle triangle.
The 3rd angle is: 180-94-56 = 30 degrees
If each base angle is 56°, then the vertex angle is 68°.If both base angles combined total 56°, then the vertex angle is 124°.
Assuming a right-angle triangle whose length is vertical, and the width is the base, then (14×8) ÷ 2 = 56 square units.
Acute triangle - all of the angles are less than a right angle (90°).Scalene triangle - none of the sides or angles are congruent. It can be shown that if no two angles are the same, then no two sides are the same using the Law of Sines and Law of Cosines.
If that '56' has units of 'degrees', then the vertex angle is 68 degrees.
56 degrees
62 degrees
Vertex angle = 180 - 2(62) = 56 degrees
Well, in any triangle, the sum of all its angles is 180 degrees. If you know that it is a right-angled triangle, then you automatically know that it has a 90 degree angle. And since it also has a 34 degree acute angle. The third angle add with 90 and 34 to equal 180.Lets call the third angle 'x'x+90+34 = 180Simplifyx+124 = 180Subtract 124 from both sidesx = 56So the third angle is 56 degrees.Therefore, your three angles are 90, 34 and 56 degrees.