i think your a bit confused (or have written your question wrongly). n is an unknown (as you didnt state otherwise), and can take any value. n could equal 1 (1 squared -25*1 +84doesnt equal 0), therefore you cannot show that your expression equals 0.
i assume you meant to ask us to solve the equation you gave (which would mean you are asking for the values of n, which satisfy the equation), so this is what i shall do.
To solve this, as it is a quadratic equation, you first look to factorise (if this doesn't work, use the quadratic formula):
To factorise the equation: n^2 - 25n + 84 = 0, you need to find two numbers which multiply to give +84, and add together to give -25. these numbers are -3 and -28 (by trial and error). therefore n^2 - 25n + 84 = (n-3)(n-28) = 0
and the only way two numbers multiply together to get 0, is if either (or both) numbers are 0.
therefore: n - 3 = 0
which gives the solution n=3
or: n - 28 = 0
which gives the solution n=28
therfore the solutions are n=28 or n=3
n = 4 25 x n = 25 x 4 25n = 100
Assuming you meant 7n (not just 7 at the end of your question) - first... simplify the equation. Numbers raised to powers get priority - so your new sum is... 5n - 64n + 25n + n + 7n.... This simplifies to... -26n
19
The prime factorization of 25n^2 is 5 * 5 * n * n, or simply 5^2 * n^2. This means that the prime factors of 25n^2 are 5 and n, each raised to the power of 2. In other words, 25n^2 can be expressed as the product of 5 squared and n squared.
Sudan is the country located at coordinates 25N latitude and 45E longitude.
The city located at 25N and 111W coordinates is Hermosillo, Mexico.
To find the smallest number of terms in the arithmetic progression (AP) 325, 350, 375, ..., we first identify the first term ( a = 325 ) and the common difference ( d = 25 ). The ( n )-th term of the AP can be expressed as ( a_n = 325 + (n-1) \cdot 25 = 325 + 25n - 25 = 300 + 25n ). The sum ( S_n ) of the first ( n ) terms is given by ( S_n = \frac{n}{2} \cdot (a + a_n) = \frac{n}{2} \cdot (325 + (300 + 25n)) = \frac{n}{2} \cdot (625 + 25n) = \frac{25n^2 + 625n}{2} ). Setting this greater than 10,000 and solving for ( n ) gives ( n^2 + 25n - 800 > 0 ), leading to ( n \geq 25 ). Thus, a minimum of 25 terms is required for the sum to exceed 10,000.
The country located at coordinates 25N, 20E is Egypt. It is situated in North Africa and bordered by the Mediterranean Sea to the north.
75n
Very little. Mostly cosmetic year to year changes. In 2003, the 25N was renamed the 925.
Ghunchoo, Madhya Pradesh 471525, India
Mexico