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Solve the system of equations Y=2xY=X2 - 15?

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Frida Lopez

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Q: Solve the system of equations Y=2xY=X2 - 15?
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6x - 6y plus 11 equals 17 9y equals 3x plus 15 Solve the system of equations and enter the solution as an ordered pair?

(0,7)


Is linear algebra and linear equations the same?

Linear Algebra is a branch of mathematics that enables you to solve many linear equations at the same time. For example, if you had 15 lines (linear equations) and wanted to know if there was a point where they all intersected, you would use Linear Algebra to solve that question. Linear Algebra uses matrices to solve these large systems of equations.


What is called Substitution method?

When you have a system of equations and you can solve for one in terms of th others and then replace it in the other equations that is substitution. x+y=15 x-y=1 well the second one can be x=1+y x+y=15 then can be (1+y)+y=15 by substitution. 1+2y=15 2y=14 y=7 Then x+7=15 x=8


Answer to 5y equals x-10?

15


What equation could be used to solve for the tenth term of the following sequence 15 13 11 9?

Which of the following equations could be used to solve for the tenth term of the following sequence?15, 13, 11, 9, ...


Solve this system x - y equals 8 2x plus y equals 7?

Add the two equations: 3x = 15 Divide by 3: x = 5, making y = -3. Job done.


When you solve a system of linear equations by adding or subtracting what needs to be true about the variable terms in the equations?

I guess you mean, you want to add two equations together. The idea is to do it in such a way that one of the variables disappears from the combined equation. Here is an example:5x - y = 15 2x + 2y = 11 If you add the equations together, no variable will disappear. But if you first multiply the first equation by 2, and then add the resulting equations together, the variable "y" will disappear; this lets you advance with the solution.


How do you solve muitiplication equations?

Your question lacks precision in its expression, but basically you divide the both sides by the coefficient of the unknown. Example: solve 3x = 15. Divide both sides by 3 to get x = 5.


How do you solve 3x equals 15 plus 5y?

3X = 15 + 5y does not have a single answer. The answer forms a line on the Cartesian plane. In order to reach a single solution you must have two equations when there are two unknowns.


What two numbers have a sum of ten and a difference of twenty?

15 and -5 x + y =10 x - y = 20 So it is eventually discovered that x = 15 and y =-5, if you solve the equations.


What is consistent and dependent?

The terms consistent and dependent are two ways to describe a system of linear equations. A system of linear equations is dependent if you can algebraically derive one of the equations from one or more of the other equations. A system of linear equations is consistent if they have a common solution.An example of a dependent system of linear equations:2x + 4y = 84x + 8y = 16Solve the first equation for x:x = 4 - 2yPlug that value of x into the second equation:16 - 8y + 8y = 16, which gives 16 = 16.No new information was gained from the second equation, because we already knew 16 = 16, so these two equations are dependent.An example of an inconsistent system of linear equations:Because consistency is boring.2x + 4y = 84x + 8y = 15Solve the first equation for x:x = 4 - 2yPlug that value of x into the second equation:16 - 8y + 8y = 15, which gives 16 = 15.This is a contradiction, because 16 doesn't equal 15. Therefore this system has no solution and is inconsistent.


The sum of Barbara's and Ed's ages is 15 years. The difference is 5 years. How old are Barbara and Ed?

Without knowing which is older, you cannot assign their ages. But one is 10 and the other is 5. The idea here is to write two equations, one for the sum of the ages (B + E = 15), one for the difference. Then, solve both equations simultaneously. There are several ways to do this; for example, you can solve one of the equations for "B", and replace that variable in the other equation. x + y = 15 x = y +5 (y+5) + y = 15 2y + 5 = 15 2y = 10 y = 5 (the younger child), x = y+5 = 10 (the older child).