1+root 6 -n=3
n=1+ root 6 - 3
n=root6 -2
68
This question cannot be answered. You will have to give me the number to the square root. * * * * * a = ±sqrt(c^2 - b^2)
If x equals the square root of ...., then you already have solved for x
87
x = the square root of -1, an imaginary number written as a lower case italic i.
Yes but not me
PLUS 2
a = -4
Well, darling, to solve for t when t squared equals 169, you simply take the square root of both sides. So, t equals plus or minus the square root of 169, which is 13. Easy peasy lemon squeezy. Now go show off your math skills, honey!
if x^2 = 49, then the square root property says you can take the square root of both sides as long as you make one a plus-minus. x^2 = 49, which means square root of x^2 = plus minus the square root of 49 the square root of 49 is 7, so +- 7. We get: x = plus/minus 7 (this means either positive 7 or negative 7)
It depends on which variable you wish to solve for.
Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.