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Q: Solve for x to 27x - 3 equals 105?

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27x-3=105 27x =105+3 27x = 108 27x/27=108/27 x= 4

Is the same as: 27x+1 = 3 Deduct 1 from both sides: 27x+1-1 = 3-1 27x = 2 Divide both sides by 27: x = 2/27

To solve this we simply plug in the value of x where any x's are found in the equation. 1) 27x - 27; x = -9 2) 27(-9) - 27 3) -243 - 27 = -270 So, 27x - 27 = -270 if x = -9.

No. The solution to the equation is 1/3. To solve: 27x - 5 = 4 (add 5 to each side to separate knownsa from inkowns) 27x = 9 (now divide both sides by 27 to find the value of x) x = 1/3 (solution)

20x^2 + 27x + 9 = 0 20x^2 + 15x +12x + 9 = 0 5x(4x + 3) + 3(4x + 3) = 0 (5x + 3)(4x + 3) = 0 So either (5x + 3) = 0 which yields x = -3/5 or (4x + 3) = 0 which yields x = -3/4

Related questions

27x-3=105 27x =105+3 27x = 108 27x/27=108/27 x= 4

X = 1/3

Is the same as: 27x+1 = 3 Deduct 1 from both sides: 27x+1-1 = 3-1 27x = 2 Divide both sides by 27: x = 2/27

To solve this we simply plug in the value of x where any x's are found in the equation. 1) 27x - 27; x = -9 2) 27(-9) - 27 3) -243 - 27 = -270 So, 27x - 27 = -270 if x = -9.

No. The solution to the equation is 1/3. To solve: 27x - 5 = 4 (add 5 to each side to separate knownsa from inkowns) 27x = 9 (now divide both sides by 27 to find the value of x) x = 1/3 (solution)

0.3333

20x^2 + 27x + 9 = 0 20x^2 + 15x +12x + 9 = 0 5x(4x + 3) + 3(4x + 3) = 0 (5x + 3)(4x + 3) = 0 So either (5x + 3) = 0 which yields x = -3/5 or (4x + 3) = 0 which yields x = -3/4

35 * 3 = 105

cube root of 27 = 3, so 3^12 = 531 441 * * * * * If the question is about 27x, rather than 27, the answer is as follows: cuberoot(27x12) = (27x)12/3 = (27x)4 = 531441x4

3 times 35 equals 105

3, 5 and 97

As a product of its prime factors: 3*5*7 = 105