27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3
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sqrt(27x)9 = (27x)9/2 = 27x4.5 While that can be simplified somewhat, it will leave a surd - sqrt(3x) - in the answer. Whether or not simplification is worthwhile, therefore, depends on what is to be done with the answer. > sq. root ( 279) ? on calculator: 27, x^y, 9, =, inv, x^2 > 2761448.4397
It is: 23-27x when simplified
X = 1/3
27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3
The square root of 275 = 3787.995116
19
sqrt(27x)9 = (27x)9/2 = 27x4.5 While that can be simplified somewhat, it will leave a surd - sqrt(3x) - in the answer. Whether or not simplification is worthwhile, therefore, depends on what is to be done with the answer. > sq. root ( 279) ? on calculator: 27, x^y, 9, =, inv, x^2 > 2761448.4397
-122.10267
0.2963
Your question is ambiguous. (3x)^3 times (3x)^3 = 27x^3 times 27x^3 = 729x^6 or, if you meant 3x^3 times 3x^3 = 9x^6
the answer is (3x-2)(9x squared+6x+4)
(8x + 9)(3x^2 - 1)
I also need to know the answer to this problem. Can anyone answer it?
0
In order to factor the sum of the cubes, we need to use this form a³ + b³ = (a + b)(a² - ab + b²). Let a³ = 27x³ and b³ = 343y³. Then, a = 3x and b = 7y. Perform substitution of these terms for the form, and we obtain: 27x3 + 343y3 = (3x + 7y)(9x2 - 21xy + 49y2)