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6x-12 plus 4x plus 5?
6x - 12 + 4x + 5 = 06x + 4x = 12 - 510x = 7x = 7/10
If you invested 7000 in two accounts paying 6 percent and 8 percent annual interest respectively If the total interest earned for the year was 520 how much was invested at each rate?
.06x+.08y=520 x+y=7000 solve for either the x or y in the x+y=7000 problem: y=7000-x now subsitute your new equation in for y: .06x+.08(7000-x)=520 now solve: .06x+560-.08x=520 -560 -560 .06x-.08x=-40 -.02x=-40 -.02 -.02 x=2000 then plug x into your x+y=7000 equation: 2000+y=7000 y=5000 SOOO, x=2000 @ 6%, y=5000 @8%
Log 5 plus log 2 equals?
log (6x + 5) = 26x + 5 > 06x + 5 - 5 > 0 - 56x > - 56x/6 > -5/6x > -5/6log (6x + 5) = 210^2 = 6x + 5100 = 6x + 5100 - 5 = 6x + 5 - 595 = 6x95/6 = 6x/695/6 = xCheck:
What is the mass of 0.06 moles of zinc?
.06x molar mass of zinc which is the atomic mass so 3.9228 g
Find the coordinates of the foot of the perpendicular from -25 to 3x y 11 0?
x-y +1 =06x=6y-7
5x plus 9y equals 0 6x plus 6y equals 2?
5x + 9y = 06x + 6y = 2 use substitution method5x + 9y = 0y = -5x/96x + 6y = 2 substitute y with -5x/96x + 6(-5x/9) = 26x - 30x/9 = 2 multiply by 9 to both sides54x - 30x = 1824x = 18x = 24/18 = 4/3y = -5x/9 = (-5/9)x substitute x with 4/3y = (-5/9)(4/3) = -20/27Thus the solution is x = 4/3 and y = -20/27.
If 5 liters of a 4 percent silver iodide solution must be mixed with a 10 percent solution to get a 6 percent solution How many liters of the 10 percent solution are needed?
Let x be the number of liters of the 10% solution needed. The amount of silver iodide in the 5-liter solution is 0.04 * 5 = 0.2 liters. The final amount of silver iodide in the mixture would be 5 * 0.06 = 0.3 liters. Set up the equation: 0.1x + 0.2 = 0.3, solve for x, x = 1 liter. Hence, 1 liter of the 10% solution is needed.
