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A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 50?
To create a 50% chlorinated solution from the 60% and 40% solutions, the chemist will need to mix the two in equal amounts. Therefore, 50 L of the 60% solution and 50 L of the 40% solution are needed to make a 100 L solution that is 50% chlorinated.
How much pure water must be mixed with 10 liters of a 25 percent acid solution to reduce it to a 10 percent acid solution?
To reduce a 25% acid solution to 10%, the water needed can be calculated using the formula: (10 x (25-10))/(10) = 1.5 liters. So, 1.5 liters of pure water must be mixed with the 10 liters of 25% acid solution to reduce it to 10%.
How many liters would you need to get 0.5moles if you had 0.1m solution?
To find out how many liters of a 0.1 M solution are needed to obtain 0.5 moles, you can use the formula: [ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} ] Rearranging this gives: [ \text{liters of solution} = \frac{\text{moles of solute}}{\text{Molarity (M)}} ] Substituting in the values: [ \text{liters of solution} = \frac{0.5 \text{ moles}}{0.1 \text{ M}} = 5 \text{ liters} ] Therefore, you would need 5 liters of a 0.1 M solution to obtain 0.5 moles.
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl and The answer is 1.64l so how do u solve it?
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl it will take a lot of thinking. The answer to this question is 1.64L.
How many liters of a 0.250 M BaCl2 solution are needed to react with 0.0325 L of a 0.160 M Na2SO4 solution?
The answer is 20,79 mL (0,021 L).
How many liters of 93 percent acid solution are needed to make a 9 percent solution with 50 liters of water?
4.84
Jerry is experimenting with chemicals in the laboratory He mixes a solution that is 10 percent acid with a solution that is 30 percent acid How much of the 10 percent acid solution will be needed to m?
10 liters
A chemist has one solution that is 60 percent chlorinated and another that is 40 percent chlorinated How much of each solution is needed to make a 100 liter solution that is 50 percent chlorinated?
50 Liters of the 60% solution.
Mary is experimenting with chemicals in the laboratory She mixes a solution that is 10 percent acid with a solution that is 25 percent acid How much of the 10 percent acid solution will be needed to m?
16 2/3 liters
How many liters of 9 percent salt solution and 18 percent salt solution are needed to make 18 liters of 10 percent salt solution?
A. 16 of 18 percent and 2 of 9 percent b. 14 of 18 percent and 4 of 9 percent c. 16 of 9 percent and 2 of 18 percent d. 14 of 9 percent and 4 of 18 percent
How many moles of potassium iodide are needed to make 750 ml of a 1.8 M solution?
To find the number of moles of potassium iodide needed, multiply the volume of the solution (750 ml) by the molarity (1.8 moles/L). First, convert the volume to liters (750 ml = 0.75 L), then multiply 0.75 L by 1.8 moles/L to get 1.35 moles of potassium iodide.
A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 50?
To create a 50% chlorinated solution from the 60% and 40% solutions, the chemist will need to mix the two in equal amounts. Therefore, 50 L of the 60% solution and 50 L of the 40% solution are needed to make a 100 L solution that is 50% chlorinated.
How much calcium hypochlorite powder at 65 percent strength is needed to make 200 liters of 2 percent hypochlorite solution?
You would need 6.15 kg of calcium hypochlorite powder at 65% strength to make 200 liters of 2% hypochlorite solution.
How much pure water must be mixed with 10 liters of a 25 percent acid solution to reduce it to a 10 percent acid solution?
To reduce a 25% acid solution to 10%, the water needed can be calculated using the formula: (10 x (25-10))/(10) = 1.5 liters. So, 1.5 liters of pure water must be mixed with the 10 liters of 25% acid solution to reduce it to 10%.
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the first 80 percent solution is needed to make a 400 L solution that is 62 percent acid?
To create a 400 L solution that is 62% acid, you would need 200 L of the 80% acid solution and 200 L of the 30% acid solution. This would result in a final solution with the desired concentration.
How many liters of a 0.30M solution are needed to give 2.7 moles of solute?
Calc.:2.7 (mol) / 0.30 (mol/L) = 9.0 L
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the second 30 percent solution is needed to make a 400 L solution that is 62 percent acid?
144liters
