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mx = 5y + 4

7x + 6y + 5 = 0

If they have the same slope, then we know that Δy/Δx in the first line is equal to Δy/Δx in the second one. Let's solve the second equation for y then:

y = (5 + 7x) / -6
∴y = (-7/6)x - 5/6

So we know it's slope is -7/6. Now let's rearrange our other line appropriately:

y = (m/5)x - 4/5
So the slope of our second line is m/5, which we know is the same as the slope of our other line, -7/6. We can say then that:

m/5 = -7/6
∴m = -35/6 = -55/6 ≈ -5.8333...

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Q: Straight line mx equals 5y plus 4 has same gradient as line 7x plus 6y plus 5 Find value of m?
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Related questions

How do you find the exact value of the gradient of the curve with equation y equals 1 divide by 4 minus x2 at the point where x equals 1 over 2?

You find the gradient of the curve using differentiation. The answer is 0.07111... (repeating).


Can any 2 points on a straight line be used to find the gradient?

Yes beccause: (y1-y2)/(x1-x2) = gradient


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