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No. The change of the area is the square of the change of the length and width.

If the length and width are 40% more, they got multiplied by 1.4 .

So the area got multiplied by (1.4)2 = 1.96 . That's an increase of 96% .

Q: Suppose the length and width of rectangle is 40 percent more is area also 40 percent more?

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Suppose the width=x so the length will be= (2x+3) Now perimeter of rectangle = 2(length+width) so, 186=2(x+2x+3) or, 3x+3=93 or, 3x=90 so, x=30 so the width of the rectangle is 30meters

the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle

A rectangle with width 4 can have any length!

10x2

For a rectangle or square, Area = Length * Width So Length = Area / Width.

Related questions

The length of the rectangle is 18cm. The width of the rectangle is 9cm.

if the length is 36 on a rectangle then what is the width of the rectangle

The width and length of a rectangle are two of its main dimensions. The width is the measurement of the shorter side of the rectangle, while the length is the measurement of the longer side. The area of a rectangle is calculated by multiplying the width by the length.

width=9 length=18

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

It is the area of the rectangle which is length times width

Suppose the width=x so the length will be= (2x+3) Now perimeter of rectangle = 2(length+width) so, 186=2(x+2x+3) or, 3x+3=93 or, 3x=90 so, x=30 so the width of the rectangle is 30meters

Length = 4, Width = 2

the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle

A rectangle with width 4 can have any length!

The width is the smaller length.

10x2