10x2
You forgot to put in the length of the rectangle's perimeter.
w=8in l=13in
The dimensions of the rectangle are 21 units by 9 units
6
12 meters
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
width=5 length=12
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
You forgot to put in the length of the rectangle's perimeter.
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
w=8in l=13in
length + width = 20/2 = 10 length = 7cm, width = 3cm
Length = 20 m and width = 9 m
The dimensions of the rectangle are 21 units by 9 units
6
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.