10x2
You forgot to put in the length of the rectangle's perimeter.
w=8in l=13in
The dimensions of the rectangle are 21 units by 9 units
6
12 meters
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
width=5 length=12
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
You forgot to put in the length of the rectangle's perimeter.
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
w=8in l=13in
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
length + width = 20/2 = 10 length = 7cm, width = 3cm
Length = 20 m and width = 9 m
The dimensions of the rectangle are 21 units by 9 units
6
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.