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Q: The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?

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If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.

If it's a rectangle, just minus the length from the perimeter twice and than divide what you have by 2. Width = (Perimeter - (length*2))/2

Given: p = 26cm and 2x width - 5cm = length p = 2(a+b) = 26cm; a+b = 13cm 2x6-5=7 The sides of the rectangle are: width 6cm and length 7cm

The dimensions are 16 units by 8 units of mearsurement

Designate the width by w. Then, from the problem statement, the length = 6 + 2w. The perimeter is twice the width plus twice the length, or: 2w + 2(2w + 6) = 36; or 2w + 4w + 12 = 36; or 6w = 24 or w = 4 meters; the length is 14 meters.

Related questions

If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)

The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

The dimensions of the rectangle are 21 units by 9 units

width=15 length=35

A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.

4cm by 13cm

The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in

Area is length times width, perimeter is twice the sum of length and breadth.

The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar

twice length + twice width = perimeter In this example, L= 3W 2(3W)+2(W)=64 8W=64 W=6 L =3W L=18 The dimensions of this rectangle are: 18 by 6

Length = (Perimeter - twice width) / 2

Perimeter of a rectangle = twice (length + width), in this case 22 m.

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