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. the equation of a straight line can be found by using two points on a line
. First find the gradient of the line using the gradient formula
. now substitute the gradient into general form replacing "m"
. use one of the points and substitute into equation to solve "c"
example 1: find the equation of the line which passes through the points (1,3) and (2,5).
step 1: find the gradient M=5-3/2-1=2 (/=divide)
step 2: place m into the equation Y=2x+c
step 3: substitute point into equation 3=2(1)+c
step 4: solve C=1
equation is Y=2x+1
hope that helps :)
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How do you write an equation in slope-intercept form of the line passing through each pair of points?
y=mx+c where x and y are variables, m is the gradient (or slope) and c is the intercept on y (axis). that is the general equation of a straight line. if you had given some coordinates for the points one could extrapolate from that to find the full equation. since you have not, one cannot.
Find the slope of a line passing through the points 2 -5 and -1 -8?
Use the equation y1-y2/x1-x2 PLug in the numbers -5--8/2--1 Solve 3/3 The Slope is 1
How do you find the equation of a parabola in standard form given 3 points?
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.
How can you find an equation line between two pair of points?
Assuming you want the equation of the straight line between the two points (x0, y0) and (x1, y1), the equation is: y - y0 = m(x - x0) where m is the gradient between the two points: m = (y1 - y0) ÷ (x1 - x0) Note: if the two x coordinates are equal, that is x0 = x1, then the equation of the line is x = x0.
One way to find the equation of a line is to look at some points on it and try to find the relationship between the coordinates?
Yes. You need only two points. If A (ax, ay) and B (bx, by) are two points on the line then the gradient (slope) of the line is m = (by - ay)/(bx - ax) provided bx ≠ ax. From this you can calculate m. Then the general slope-intercept form of the equation is y = mx + c Substitute the coordinates of A or B into this equation to find c. If bx = ax then the line is parallel to the y axis and its equation is x = ax. [There are other methods but they are similar to the above]
Find an equation in standard form for the passing through the points 1 4 and -3 4?
6666
How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
How do you write an equation in slope-intercept form of the line passing through each pair of points?
y=mx+c where x and y are variables, m is the gradient (or slope) and c is the intercept on y (axis). that is the general equation of a straight line. if you had given some coordinates for the points one could extrapolate from that to find the full equation. since you have not, one cannot.
Is it easier to solve an equation for y first before finding points?
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
What is the slope of the line passing through points a 5 4?
Another set of points are needed to find the slope.
What is the equation of a line that passes through the points 2 5 and 4 3?
Points: (2, 5) and (4, 3) Slope: -1 Equation: y = -x+7 in slope-intercept form --- If you want to write the slope-intercept form of the equation of the line passing through the given points, then use the two points to find the slope of the line. After that, use the slope and one of the points to find the y-intercept. For instance, m = (5 - 3)/(2 - 4) = 2/-2 = -1(the slope) y = mx + b (replace m with -1, and (x, y) with (4, 3)) 3 = -1(4) + b 3 = -4 + b (add 4 to both sides) 7 = b Thus, y = -x + 7 is the equation of the line passing through (2, 5) and (4, 3).
How do you find the straight line equation passing through the points -7 -3 and -1 -4?
First find the slope and then use the fact that y = mx+c where m is the slope and c is the intercept on the y axis to find the equation. Slope: -4 - -3 over -1 - -7 = -1/6 Equation: y = -1/6x -25/6 or 6y = -x -25
What is a chord passing through the center of a circle?
a diameter
What is the slope of a line passing through the two points - Round your answer to the nearest tenth?
That depends on the points in order to find the slope whereas no points have been given.
How do you find Slope intercept equation of given two points?
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
What is the equation of the line passing through the points 2 -4 and -1 2?
y=-2xExplanationYou could find the slope of line going through the points (2,-4) and (-1,2). It isslope is -6/3 or -2So the line isNow plug in one of the points and the slope into point slope form and find the liney+4=-2(x-2) ory+4=-2x+4 soy=-2xCheck it by making sure BOTH points are on the line. Plug the values into the equation you found for the line.-4=-2(2)2=-2(-1)
Find the slope of a line passing through the points 2 -5 and -1 -8?
Use the equation y1-y2/x1-x2 PLug in the numbers -5--8/2--1 Solve 3/3 The Slope is 1
