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. the equation of a straight line can be found by using two points on a line
. First find the gradient of the line using the gradient formula
. now substitute the gradient into general form replacing "m"
. use one of the points and substitute into equation to solve "c"
example 1: find the equation of the line which passes through the points (1,3) and (2,5).
step 1: find the gradient M=5-3/2-1=2 (/=divide)
step 2: place m into the equation Y=2x+c
step 3: substitute point into equation 3=2(1)+c
step 4: solve C=1
equation is Y=2x+1
hope that helps :)
What else can I help you with?
How do you write an equation in slope-intercept form of the line passing through each pair of points?
y=mx+c where x and y are variables, m is the gradient (or slope) and c is the intercept on y (axis). that is the general equation of a straight line. if you had given some coordinates for the points one could extrapolate from that to find the full equation. since you have not, one cannot.
Find the slope of a line passing through the points 2 -5 and -1 -8?
Use the equation y1-y2/x1-x2 PLug in the numbers -5--8/2--1 Solve 3/3 The Slope is 1
How do you find the equation of a parabola in standard form given 3 points?
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.
How can you find an equation line between two pair of points?
Assuming you want the equation of the straight line between the two points (x0, y0) and (x1, y1), the equation is: y - y0 = m(x - x0) where m is the gradient between the two points: m = (y1 - y0) ÷ (x1 - x0) Note: if the two x coordinates are equal, that is x0 = x1, then the equation of the line is x = x0.
How do you find other points on the parabola?
To find other points on a parabola, you can use its equation, typically in the form (y = ax^2 + bx + c). By selecting different values for (x) and substituting them into the equation, you can calculate the corresponding (y) values. Alternatively, you can also use the vertex form, (y = a(x-h)^2 + k), where ((h, k)) is the vertex, to find points by choosing (x) values around the vertex. Plotting these points will help visualize the shape of the parabola.
Find an equation in standard form for the passing through the points 1 4 and -3 4?
6666
How do you draw a flow chart to find the equation of a circle passing through three given points?
To draw a flowchart for finding the equation of a circle passing through three given points, start by defining the three points as ( A(x_1, y_1) ), ( B(x_2, y_2) ), and ( C(x_3, y_3) ). Next, set up the general equation of a circle ( (x - h)^2 + (y - k)^2 = r^2 ) and derive a system of equations by substituting the coordinates of the points into this equation. Solve the resulting system of equations for the center coordinates ( (h, k) ) and the radius ( r ), and finally, express the equation of the circle in standard form.
How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
How do you write an equation in slope-intercept form of the line passing through each pair of points?
y=mx+c where x and y are variables, m is the gradient (or slope) and c is the intercept on y (axis). that is the general equation of a straight line. if you had given some coordinates for the points one could extrapolate from that to find the full equation. since you have not, one cannot.
Is it easier to solve an equation for y first before finding points?
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
What is the slope of the line passing through points a 5 4?
Another set of points are needed to find the slope.
What is the equation of a line that passes through the points 2 5 and 4 3?
Points: (2, 5) and (4, 3) Slope: -1 Equation: y = -x+7 in slope-intercept form --- If you want to write the slope-intercept form of the equation of the line passing through the given points, then use the two points to find the slope of the line. After that, use the slope and one of the points to find the y-intercept. For instance, m = (5 - 3)/(2 - 4) = 2/-2 = -1(the slope) y = mx + b (replace m with -1, and (x, y) with (4, 3)) 3 = -1(4) + b 3 = -4 + b (add 4 to both sides) 7 = b Thus, y = -x + 7 is the equation of the line passing through (2, 5) and (4, 3).
How do you find the straight line equation passing through the points -7 -3 and -1 -4?
First find the slope and then use the fact that y = mx+c where m is the slope and c is the intercept on the y axis to find the equation. Slope: -4 - -3 over -1 - -7 = -1/6 Equation: y = -1/6x -25/6 or 6y = -x -25
What is a chord passing through the center of a circle?
a diameter
Where an equation crosses the horizontal axis?
An equation crosses the horizontal axis at points where the output value (usually represented by (y)) is zero. These points are known as the roots or x-intercepts of the equation. To find these points, you set the equation equal to zero and solve for the variable, typically represented as (x). Graphically, this represents the points where the graph of the equation intersects the x-axis.
How do you find Slope intercept equation of given two points?
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
What is the slope of a line passing through the two points - Round your answer to the nearest tenth?
That depends on the points in order to find the slope whereas no points have been given.
