. the equation of a straight line can be found by using two points on a line
. First find the gradient of the line using the gradient formula
. now substitute the gradient into general form replacing "m"
. use one of the points and substitute into equation to solve "c"
example 1: find the equation of the line which passes through the points (1,3) and (2,5).
step 1: find the gradient M=5-3/2-1=2 (/=divide)
step 2: place m into the equation Y=2x+c
step 3: substitute point into equation 3=2(1)+c
step 4: solve C=1
equation is Y=2x+1
hope that helps :)
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y=mx+c where x and y are variables, m is the gradient (or slope) and c is the intercept on y (axis). that is the general equation of a straight line. if you had given some coordinates for the points one could extrapolate from that to find the full equation. since you have not, one cannot.
Use the equation y1-y2/x1-x2 PLug in the numbers -5--8/2--1 Solve 3/3 The Slope is 1
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.
Assuming you want the equation of the straight line between the two points (x0, y0) and (x1, y1), the equation is: y - y0 = m(x - x0) where m is the gradient between the two points: m = (y1 - y0) ÷ (x1 - x0) Note: if the two x coordinates are equal, that is x0 = x1, then the equation of the line is x = x0.
Yes. You need only two points. If A (ax, ay) and B (bx, by) are two points on the line then the gradient (slope) of the line is m = (by - ay)/(bx - ax) provided bx ≠ ax. From this you can calculate m. Then the general slope-intercept form of the equation is y = mx + c Substitute the coordinates of A or B into this equation to find c. If bx = ax then the line is parallel to the y axis and its equation is x = ax. [There are other methods but they are similar to the above]