2=w
The expression for 7 times the sum of ( c ) and 2 can be written as ( 7 \times (c + 2) ). This means you first add 2 to ( c ), and then multiply the result by 7. Therefore, the final expression is ( 7(c + 2) ).
a^2 + b^2=c^2
36
int a = 1; int b = 2; int c = a + b; // Sum
You add 2 fractions with the same denominator [c], so the sum is the sum of the numerators divided by the denominator: a/c + b/c = (a+b)/c
7 * (c + 2) = 7 * c + 14
(c+4)/2
In a right triangle, the sum of the squares of the legs (a and b) is equal to the square of the hypotenuse (c), as described by the Pythagorean theorem: (a^2 + b^2 = c^2). If the sum of the squares of the legs is 144, then (c^2 = 144). Taking the square root gives (c = \sqrt{144} = 12). Therefore, the hypotenuse is 12.
In Java:sum = 0;for (i = 2; i
To solve for the sum of the first n number of cubes, use (1+2+3+4+5...+n)2. So for n=100, (1+2+3+4+5...+100)2 = c (cubes) (101 * 50)2 = c 50502 = c c = 25502500
int i, sum = 0; for (i=0; i<20; i+=2) sum+=i;
The expression can be written as (2 + c)/2 - 6b.