a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
If a + b + c + d + 80 + 90 = 100, then a + b + c + d = -70.
A=8 B=4 C=14 Yes, I know I'm a genius. Mak - the all knowing one. MWAHAHAH!
{ int a,b; { a=a^2; } { b=b^2; } { c=a^2+b^2+2*a*b; print f("%d%d%d",&c); get ch(); } ]
d a tool for analysing c plus plus program
b+b+b+c+c+c+c =3b+4c
b + b + b + c + c + c + c = 3b + 4c
It is impossible to give any decimal/numeric value if we are not given the values of at least one variable, so the answer is B + B + B + C + C + C.
2b + 2c or 2(b + c)
And how does this relate to coins?
If your Problem is organized like this: A x squared plus B x plus C, the equation is: (B plus or minus the square root of(B squared minus 4 A C)) over 2A
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
A+c= 2a+b
If a + b + c + d + 80 + 90 = 100, then a + b + c + d = -70.
If: a = b+c+d Then: c = a-b-d
Because there is no way to define the divisors, the equations cannot be evaluated.
x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0