answersLogoWhite

0


Best Answer

To start with, 192/3 = 64.

To get three consecutive even numbers, we simply add and subject 2 to either side. Essentially, since 64+64+64 = 192, then so does (64-2) + 64 + (64+2).

62 + 64 + 66 =192

66/3=33. So one is a multiple of 3.

User Avatar

Michael Scalise

Lvl 12
2y ago
This answer is:
User Avatar
More answers
User Avatar

AnswerBot

6mo ago

Let's call the first even number x. The next two consecutive even numbers would be x + 2 and x + 4. Given that the sum of these three numbers is 192, we can set up the equation x + (x + 2) + (x + 4) = 192. Solving for x, we find that x = 62. Therefore, the three consecutive even numbers are 62, 64, and 66. To find a number that is a multiple of 3, we can choose any number divisible by 3, such as 69 or 72.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: The sum of three consecutive even numbers is 192. Find the threenumbers and one number which is multiple of 3?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What 3 consecutive numbers add up to 76?

79


Why can there never be a pair of consecutive prime numbers that are both prime?

If you mean consecutive numbers that are prime? than the answer is 2,3 are consecutive numbers which are prime. except for this pair it is impossible for consecutive numbers to be prime because every second number is multiple of 2


What are 3 consecutive numbers whose sum is 125?

That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.


What three consecutive odd numbers have a sum of 46?

Can't be done. The number has to be a multiple of 3.


Three consecutive numbers that add up to a multiple of three?

EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.


Can 2 consecutive numbers in prime factorization be prime?

The only one pair of consecutive prime numbers possible are 2 and 3. After these very two numbers, every even number is a multiple of two. Furthermore, after 10, every number ending if five is a multiple of five. So, then no two prime numbers can be consecutive anymore. The span between prime numbers then only get wider and wider as the numbers continue to count upwards.


How many consecutive numbers do you need to guarantee that one of the numbers is divisible by 6?

Every sixth number will be a multiple of 6, so you need at least six consecutive numbers to guarantee that one of them will be divisible by 6.


What three consecutive numbers add up to 25?

That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).


The HCF of two consecutive numbers is always?

A factor is a number of which the number being considered is a multiple. Two consecutive numbers cannot both be multiples of 4, for instance, as there isn't 3 numbers in between them. They cannot in fact be multiples of any common number other than 1. Thus the HCF of two consecutive numbers must always be 1.


How can you find the gcf of two numbers without knowing the factors?

If one of the numbers is a multiple of the other, the smaller number is the GCF. If the two numbers are prime numbers, the GCF is 1. If the numbers are consecutive, the GCF is 1. If the numbers are consecutive even numbers, the GCF is 2.


Can two consecutive numbers be even. Why or Why not?

No, because every other number in the number line is odd so therefore if you have any number of consecutive numbers you will have at least one odd number (if you're talking about consecutive numbers on a number line).


What is the definition of a consecutive prime number?

Consecutive prime numbers are two prime numbers that are next to each other, with no other prime numbers in between. For example, 3 and 5 are consecutive prime numbers.