Let's call the first even number x. The next two consecutive even numbers would be x + 2 and x + 4. Given that the sum of these three numbers is 192, we can set up the equation x + (x + 2) + (x + 4) = 192. Solving for x, we find that x = 62. Therefore, the three consecutive even numbers are 62, 64, and 66. To find a number that is a multiple of 3, we can choose any number divisible by 3, such as 69 or 72.
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If you mean consecutive numbers that are prime? than the answer is 2,3 are consecutive numbers which are prime. except for this pair it is impossible for consecutive numbers to be prime because every second number is multiple of 2
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
Every sixth number will be a multiple of 6, so you need at least six consecutive numbers to guarantee that one of them will be divisible by 6.
Prime number next to any prime number is called consecutive prime number. Eg:- 2,3,5,7 are prime numbers
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If you mean consecutive numbers that are prime? than the answer is 2,3 are consecutive numbers which are prime. except for this pair it is impossible for consecutive numbers to be prime because every second number is multiple of 2
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
Can't be done. The number has to be a multiple of 3.
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
The only one pair of consecutive prime numbers possible are 2 and 3. After these very two numbers, every even number is a multiple of two. Furthermore, after 10, every number ending if five is a multiple of five. So, then no two prime numbers can be consecutive anymore. The span between prime numbers then only get wider and wider as the numbers continue to count upwards.
Every sixth number will be a multiple of 6, so you need at least six consecutive numbers to guarantee that one of them will be divisible by 6.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
A factor is a number of which the number being considered is a multiple. Two consecutive numbers cannot both be multiples of 4, for instance, as there isn't 3 numbers in between them. They cannot in fact be multiples of any common number other than 1. Thus the HCF of two consecutive numbers must always be 1.
If one of the numbers is a multiple of the other, the smaller number is the GCF. If the two numbers are prime numbers, the GCF is 1. If the numbers are consecutive, the GCF is 1. If the numbers are consecutive even numbers, the GCF is 2.
No, because every other number in the number line is odd so therefore if you have any number of consecutive numbers you will have at least one odd number (if you're talking about consecutive numbers on a number line).
Prime number next to any prime number is called consecutive prime number. Eg:- 2,3,5,7 are prime numbers