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The sum of three consecutive even numbers is 192. Find the threenumbers and one number which is multiple of 3?
To start with, 192/3 = 64.
To get three consecutive even numbers, we simply add and subject 2 to either side. Essentially, since 64+64+64 = 192, then so does (64-2) + 64 + (64+2).
62 + 64 + 66 =192
66/3=33. So one is a multiple of 3.
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RossLet's call the first even number x. The next two consecutive even numbers would be x + 2 and x + 4. Given that the sum of these three numbers is 192, we can set up the equation x + (x + 2) + (x + 4) = 192. Solving for x, we find that x = 62. Therefore, the three consecutive even numbers are 62, 64, and 66. To find a number that is a multiple of 3, we can choose any number divisible by 3, such as 69 or 72.
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