Let's set up an inequality to represent all possible values of the width (w) of the rectangle given the information provided.
The length of the rectangle is three times its width, so the length (L) can be expressed as L = 3w.
The perimeter (P) of a rectangle is given by the formula: P = 2(L + w).
The perimeter is greater than 64 centimeters, so we have P > 64.
Now, substitute the expression for L from step 1 into the perimeter formula from step 2:
P = 2(3w + w)
Simplify the expression inside the parentheses:
P = 2(4w)
P = 8w
Now, we have the perimeter in terms of the width: P = 8w.
We already know that P > 64, so we can write the inequality:
8w > 64
To isolate w, divide both sides of the inequality by 8:
w > 64 / 8
w > 8
So, the inequality representing all possible values of the width (w) is:
w > 8
This means that the width of the rectangle must be greater than 8 centimeters for the perimeter to be greater than 64 centimeters.
What is the perimeter of a rectangle 5 meter by 650 centimeters?
the answer is 16 cm and that is the perimeter.
If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.
The answer is 12 cm.
Perimeter of rectangle = (length * 2) + (height * 2 Perimeter = (50.7 * 2) + (40.8 * 2) Perimeter = 183cm
22
If the shape measuring 8 centimeters by 5 centimeters is a rectangle, the perimeter of the rectangle is 25 centimeters (2w + 2l)
The perimeter of a rectangle measuring 20x45 centimeters is (2*20) + (2*45) = 40 + 90 = 130 cm
30 ft
21cm3
what is the value of x so that the perimeter of the rectangle shown is at least 92 centimeters
58 cm