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The demension of a right trapezoid-shaped figure has bases of 28 inches and 16 inches and the slant height is 17 inches What is the lenght in inches of the height?
Wiki User
∙ 14y ago
If you draw another altitude parallel to the height (the side which is perpendicular to the bases) of the trapezoid, you can see that a right triangle is formed.
In this triangle the hypotenuse length is 17 in, and the base length equals to 28 - 16 = 12 in. From the Pythagorean theorem, height length = √(17 - 12) ≈ 12 in.
Or find the measure of the angle (call it A) opposite to the height such as:
cos A = 12/17
A = cos-1 (12/17) ≈ 45â°, which tells us that this right triangle is an isosceles triangle.
Therefore, the height is (congruent with base) 12 inches long
Wiki User
∙ 14y ago
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