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The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.

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Q: The density of gold is 19.3 g cm3 The density of iron pyrite is 5.0 g cm3 If a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
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What is the density of a gold nugget that has a volume of 1.68 cm3 and a mass of 32.4 g?

With the information given, the density of your nugget is about 19.29 g/cc. The density of gold is given as about 19.3 g/cc, so your nugget fits the density requirements for it to be a gold nugget.


What is the mass of a piece of pyrite that has a volume of 40cm3?

Iron pyrite (FeS2) has a density of 4.8 to 5.0 grams per cm3. A piece of volume 40 cm3 would, therefore have a mass of volume*density = 192 to 200 grams.


What is the density of a piece of iron pyrite that has a mass of 57.2 g and a volume of 11 cm cubed?

Density = Mass/Volume = 57.2g/11 cm3 = 5.2 gcm-3


What is the mass of a 10.0 cm3 sample of pyrite?

Pyrite has a density of 4.8-5g/cm3 mass = density x volume = (4.8-5)g/cm3 x 10 cm3 = 48 to 50 grams.


A nugget of gold with a mass of 521 g is added to 50.0 mL of water The water level rises to a volume of 77.0 mL What is the density of the gold?

Assuming the gold nugget is solid and pure (unlikely in real life!) The volume of the nugget is 77.0 - 50.0 mL = 27.0 mL So density = mass/volume = 521/27.0 = 19.3 g per mL.


What are the metric measurements of a gold nugget?

The answer depends on what characteristic of the gold nugget you wish to measure: its mass, weight, volume, density, temperature, electrical conductivity, etc.


An irregularly shaped gold nugget weighs 24.3g and is found to displace 1.26ml of water. Can it be determined if it is really gold?

You can make a fairly good guess. What the first part of the experiment is designed to do is find the volume of the irregularly shaped nugget. Archimedes is the first to be recorded as offering this solution to finding the volume of an irregularly shaped object. By submerging the object in water, the experimenter can determine the volume of water the object displaces. By knowing the weight of the nugget and the volume of the nugget, and by comparing that to the known density of gold, you can make a fairly good guess as to whether or not it is gold. Let's look. Your nugget displaced 1.26 ml of water. That's 1.26 cubic centimeters of water. The nugget weighs 24.3 grams. Your nugget weighs 24.3 grams per 1.26 cubic centimeters. Divide this out to find the weight per 1 cubic centimeter: 24.3 grams / 1.26 cc = 19.29 grams per cubic centimeter. The density of gold, its weight per unit of volume, can be looked up with ease. As the known density of your nugget is about 19.3 grams per cubic centimeter, which is the known density of gold, there is a strong case for your nugget to be gold.


How do you calculate the denstiy of pyrite?

Compare its weight to the weight of an equal volume of water. The weight of the specimen divided by the weight of the water equals the density of the specimen.


How can you express the volume of a gold nugget using cubic units?

Submerge it in water and determine the volume (in cubic centimeters) that it displaces. That will be the volume of the nugget.


Does a large piece of wood have a greater density than a small piece of wood?

The larger piece will probably have more mass than the smaller one. But if the wood is of the same type and "all things are equal" as regards moisture content, sap content, etc., the density of both pieces of wood will be the same. Density does not depend on the size of a sample. Density is mass per unit of volume. If a large gold nugget and a small gold nugget are compared, the larger nugget will have more mass, but both nuggets will have the same density.


What is the equation for mass volume and density?

Mass = Density x Volume Density = Mass/Volume Volume = Mass/Density


If you have 80mL of water and you add a gold nugget in the water rises 225mL what is the volume of gold nugget?

145