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What is the mass of aluminum sample who volume is 10.0 cm3?
27.3 g is the mass of an aluminum sample with a volume of 10.0 cm3.
What is the mass of a 350 cm3 sample of pure silicon with a density of?
2g/cm3
The density for a sample of a pure material with a volume of 5 cm3 and a mass of 20 grams is?
The idea is to divide the mass by the volume.
What is the density of a wood block with a mass of 100 g and a volume of 125 cm3?
This density is 0,8 g/cm3.
How much cm3 would a 55.932 g sample of copper occupy if it has a density of 8.92 gcm3?
volume =mass/ density volume = 55.932/8.92 = 6.27 cm3
What is the density of 100cm3 of aluminum if it has a mass of 250g?
The density of aluminum is 2.70 g/cm3. To find the density of 100 cm3 of aluminum with a mass of 250g, divide the mass by the volume: 250g / 100 cm3 = 2.50 g/cm3. The density of the aluminum sample is 2.50 g/cm3.
What is the mass of aluminum sample who volume is 10.0 cm3?
27.3 g is the mass of an aluminum sample with a volume of 10.0 cm3.
The volume of a sample of water is 20cm3 the mass of?
In order to determine the mass of the water sample, you would need to know the density of water. The density of water is approximately 1 g/cm3. Therefore, the mass of a 20 cm3 sample of water would be 20 grams (20 cm3 * 1 g/cm3 = 20 grams).
The density of gold is 19.3 g cm3 The density of iron pyrite is 5.0 g cm3 If a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.
What is the mass of a piece of pyrite that has a volume of 40cm3?
Iron pyrite (FeS2) has a density of 4.8 to 5.0 grams per cm3. A piece of volume 40 cm3 would, therefore have a mass of volume*density = 192 to 200 grams.
What is the mass of pyrite?
the density of pyrite or fool's gold is 5.01g/cm3
What is the mass of a 350 cm3 sample of pure silicon with a density of?
2g/cm3
What is the density of a sample of ore that has a mass of 57g and occupies What is the density of a sample of ore that has a mass of 57 g and occupies 29 cm3 Answer in units of g cm3?
The density of the ore sample is 1.97 g/cm3. This value is calculated by dividing the mass of the ore (57 g) by its volume (29 cm3).
Is a Nugget real gold or fools gold if a it has a mass of 100.0 g and displaces the water level in a graduated cylinder by 15.0cm3 from 10.0cm3?
To determine whether the nugget is real gold or fool's gold, you can calculate its density. The density of gold is 19.32 g/cm3, while the density of fool's gold (iron pyrite) is about 5 g/cm3. Based on the displacement of water and the mass provided, calculate the density of the nugget using the formula: density = mass/volume. Compare the calculated density to the known densities of gold and fool's gold to identify the material.
If a rock sample has a mass of 250g and a volume of 45 cm3 show the calculation for the density of the rock sample?
density = mass/volume = 250g/45cm3 = 5.6g/cm3 (rounded to 2 sig figs)
Nickel has a density of 9.8 gcm3 lead has a density of 11.3 gcm3 if both samples have a volume of 4 cm3 what are the masses of each?
The mass of the nickel sample is 39.2 g (9.8 g/cm3 * 4 cm3), and the mass of the lead sample is 45.2 g (11.3 g/cm3 * 4 cm3).
What is the mass of a 350 cm3 sample of pure silicon with density of 2.336 gcm3?
Start by writing the formula that you probably know for density D=m/V Now plug in the data that you have: 2.336 g/cm3 = m/350 cm3 so, m = 350 x 2.336 = 817.6 g
