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Pyrite has a density of 4.8-5g/cm3

mass = density x volume

= (4.8-5)g/cm3 x 10 cm3

= 48 to 50 grams.

Q: What is the mass of a 10.0 cm3 sample of pyrite?

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27.3 g is the mass of an aluminum sample with a volume of 10.0 cm3.

2g/cm3

The idea is to divide the mass by the volume.

This density is 0,8 g/cm3.

The density is (the mass, in grams)/100 grams per cm3 .

Related questions

27.3 g is the mass of an aluminum sample with a volume of 10.0 cm3.

The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.

Iron pyrite (FeS2) has a density of 4.8 to 5.0 grams per cm3. A piece of volume 40 cm3 would, therefore have a mass of volume*density = 192 to 200 grams.

the density of pyrite or fool's gold is 5.01g/cm3

The volume of a sample of water is 20 cm3. The mass of this sample is closest to

2g/cm3

density=g/cm3 The density of Gold is 19.3g/cm3 The density of Fool's Gold (pyrite) is 5g/cm3 The question is slightly ambiguous as first written so two calculations are given: # 100/15= 6.666g/cm3 So this nugget is possibly pyrite and not gold. 100/5= 20g/cm3 So this nugget is possibly gold.

By looking up it's density in a book. The density of lead is 11.34 g/cm3 at room temperature. So the mass of a 140.0 cm3 sample of lead is 11.34 g/cm3 * 140.0 cm3 = 1588 g

density = mass/volume = 250g/45cm3 = 5.6g/cm3 (rounded to 2 sig figs)

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mercury

The first reference I consulted on line lists the density of gold as 19.32 gm/cm3,whereas the density of your sample is 19.286 gm/cm3.