x^2 + y^2 = 100
(x - 0 )^2 + ( y - 0)^2 = 10^2
This is now in the Pythagorean form.
x^2 + y^2 = r^2
The centre in Cartesian coordinates is the displacement of (x,y). Since there is no displacement , the the centre is at (0,0)
r^2 is the radius squared at 10^2 , then the radius has a length of '10'.
10. Equation of circle is x2 + y2 = r2. Consider: when x = 0 y2 must = 100 so y = 10 which describes a circle centre the origin, radius 10. Similarly when x = 10 y must be 0.
x2 + y2 = 25
x2 + y2 = 25
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
circumfrence off the circle
To work out the length of the arc on a circle, you need to work out the proportion of the full circle that the arc represents. This is the proportion of the circumference of the circle. The circumference of a circle is 2 times pi times radius or 2{pi}r A full circle has 360o so an arc created between 2 radii with an angle of ao between them has a length that is a/360 that of the full circle, ie length of arc = 2{pi}ra/360 Thus, for a circle of radius r=5yds and angle=72o, the length of the arc is: 2x{pi}x5x72/360 = 2x{pi}x5x1/5 = 2x{pi} ~= 6.28yds
Radius = 1111
The ' 1 ' in that equation is the radius.
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
sqrt 36 ie 6
10 Both the x-intercept (y=0) and the y-intercept (x=0) have a length of 10 units.
The length of the arc of ABC is 22pi. You can get this answer by completing this equation 330/360*24pi, which will give you 22pi.
chords inside circles can be any length from the diameter to almost zero length.
Circle A has more area than B
8
The center of a circle is the same for all circles but the length of the radius can change
The circles are concentric with centre (0,0). The radius of the outer circle is sqrt(72), that of the inner circle is sqrt(18). By Pythagoras, the length of the semichord is sqrt(72 - 18) = sqrt(54) units. Therefore the chord is 2*sqrt(54) = 6*sqrt(6) = 14.679 units (approx).
C=2(3.14)rThis is circumference equation for circles. If you have the circumference, you need to input it into the equation and solve for r. r is the radius of the circle, so to determine the diameter, which is 2 times the length of the radius, you just need to multiply the number you got for r times 2.