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11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11

you can also think of eqn of a circle as x2+y2=r2

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โˆ™ 2010-04-05 07:01:02
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A polynomial of degree zero is a constant term

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Q: The equation for the circle below is x2 plus y2 equals 121 What is the length of the circles radius?
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