2310
101 is the first three-digit prime number.
Just multiply the first three prime numbers together.
The first two are 6 and 28. You'd have to figure a long time to get to the next one, which is 496.
120
Start counting from ' 1 '. The first number you name that is a member of the set is the smallest integer in the set.
The first prime numbers are 2, 3, 5, 7, 11. When multiplied together the product is 2310. It is the smallest number that has the first five numbers as its factors.
Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.
12 is as it has 6 factors and is the smallest and first to have. Factors of 12= 1, 2, 3, 4, 6, and 12
101 is the first three-digit prime number.
27720
2310 has all of those as factors.
4096 is the smallest number with exactly 13 factors. (Including 1 and itself as factors).192 is the smallest number with exactly 13 properfactors, (excluding the number itself).120 is the smallest number with at least 13 factors (it has 16 factors)To find the smallest number with exactly N factors (for example, N=12):Factor N into primes, (for example, 12= 2*2*3Subtract 1 from each of the prime factors (for example, 1,1,2)Sort them by largest first (for example, 2,1,1)Raise successive prime numbers to these powers (for example, 2^2,3^1,5^1)Multiply these together (for example: 4*3*5 = 60; 60 is the smallest number with exactly 12 factors).
The first two are 6 and 28. You'd have to figure a long time to get to the next one, which is 496.
Just multiply the first three prime numbers together.
If 0 can be counted as the first number, then the smallest number is 01358. If 0 cannot be counted as the first number, the the smallest number is 10358.
OK, so maybe I'm making a fool of myself; it won't be the first time. Assume positive integers, and assume that 1 (one) is one of the factors. Also assume that any factor is used only once. If factors can be used any number of times then any number answers the question (seven ones and the number). The smallest number with 8 distinct factors is 510510. If you do not count 1 as a factor, the smallest such number is 9699690. In order, the factors would be 1, 2, 3, 5, 7, 11, 13, 17, (19).
To calculate this interesting number you need to use the five smallest prime numbers. A prime number is one which is not evenly divisible by any other number (except itself and 1). The first prime number is 2. then we have 3, 5, 7, 11, 13, 17 and so on. So, if you multiply 2 x 3 x 5 x 7 x 11 you'll get the smallest number with 5 different prime factors.