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Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.

Q: If a composite number has the first five prime numbers as factors what is the smallest number it could be?

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4 is the smallest composite number and it is not divisible by the two given numbers.

41 is a prime number. It has no composite numbers as factors.

The least 1 digit number that is composite is 4. It is because all numbers before that are prime.

It is impossible to list the infinite number of composite odd numbers.

Starting from beginning we see that 0 has infinite factors so it is a composite number and 1 is neither prime nor composite. The next number is 2 which has only two factors so it is the smallest Prime number.

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27720

It is 2 × 3 × 5 × 7 × 11 = 2310

If the number is a product of two composite numbers, it must be 16, which is the product of 4 and 4. The prime factors of 16 are 2, 2, 2, and 2. The smallest composite number is 4, so the smallest possible product of two composite numbers is 4 x 4 = 16.

All numbers have factors. Some factors are prime numbers, some are composite numbers. A factor that is a composite number is a composite factor.

Just multiply the first three prime numbers together.

All composite numbers have more than 2 factors whereas prime numbers have only 2 factors

4 is the smallest composite number and it is not divisible by the two given numbers.

41 is a prime number. It has no composite numbers as factors.

Incorrect. Square numbers are composite and have an odd number of factors.

The least 1 digit number that is composite is 4. It is because all numbers before that are prime.

Any number that has more than two factors is a composite number

5 is a prime number and is not have a composite number in its factors.