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The graph of the equation below is a circle. What is the length of the radius of the circle (x plus 5)2 plus (y plus 7)2 212?
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When The circle below is centered at the point (-1 -3) and has a radius of length 5. What is its equation?
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
Write missing expression in the program below which would print the area of circle r int input Enter the circle radius?
Area of any circle = pi*radius squared
What instrument measures the area of a circle?
A scale ie required to measure the area of a circle. We need to measure the radius of that Circle and then we can put this radius valve in below mwntioned formula & can calculate the area. A=3.14*r*r where r is radius in Cm. A is are in cm square. Hemant gautam +919099921329
What is the length of the tangent line from the point 8 2 to a point where it touches the circle of x2 plus y2 -4x -8y -5 equals 0?
The tangent of a circle is perpendicular to the radius to the point of contact (Xc, Yc).The point (Xg, Yg), the centre of the circle (Xo, Yo) and the point of contact of the tangent (Xc, Yc) form a right angle triangle.The leg from the point (Xg, Yg) to the point of contact (Xc, Yc) is the required lengthThe leg from the centre of the circle (Xo, Yo) to the point of contact (Xc, Yc) has length equal to the radius (r) of the circleThe hypotenuse is the length between the point (0, 0) and the centre of the circle (Xo, Yo).To solve this:Find the centre (Xo, Yo) of the circle, and its radius r;Use Pythagoras to find the length between the point (Xg, Yg) and the centre of the circle (Xo, Yo);Use Pythagoras to find the length between the point (Xg, Yg) and the point of contact (Xc, Yc) of the tangent - the required length.Hint: a circle with centre (Xo, Yo) and radius r has an equation of the form:(x - Xo)² + (y - Yo)² = r²Have a go at solving it now you know how, before reading the solution below:------------------------------------------------------------------------------Circle:x² + y² - 4x - 8y - 5 = 0→ x² - 4x + y² - 8y - 5 = 0→ (x - (4/2))² - (4/2)² + (y - (8/2))² - (8/2)² - 5= 0→ (x - 2)² - 4 + (y - 4)² - 16 - 5 = 0→ (x - 2)² + (y - 4)² = 25 = radius²→ Circle has centre (2, 4) and radius √25 = 5Line from centre of circle (2, 4) to the given point (8, 2):Using Pythagoras to find length of a line between two points (x1, y1) and (x2, y2):length = √((x2 - x1)² + (y2 - y1)²)To find length between given point (8, 2) and centre of circle (2, 4)→ length = √((2 - 8)² + (4 - 2)²)= √((-6)² + 2²)= √40Tangent line segment:Using Pythagoras to find length of tangent between point (8, 2) and its point of contact with the circle:centre_to_point² = tangent² + radius²→ tangent = √(centre_to_point² - radius²)= √((√40)² + 25)= √65≈ 8.06
What is the length of the tangent line from the point -2 3 to a point where it touches the circle of x2 plus y2 plus 6x plus 10y -2 equals 0?
The tangent of a circle is perpendicular to the radius to the point of contact (Xc, Yc).The point (-2, 3), the centre of the circle (Xo, Yo) and the point of contact of the tangent (Xc, Yc) form a right angle triangle.The leg from the point (-2, 3) to the point of contact (Xc, Yc) is the required lengthThe leg from the centre of the circle (Xo, Yo) to the point of contact (Xc, Yc) has length equal to the radius (r) of the circleThe hypotenuse is the length between the point (-2, 3) and the centre of the circle (Xo, Yo).To solve this:Find the centre (Xo, Yo) of the circle, and its radius r.Use Pythagoras to find the length between the point (-2, 3) and the centre of the circle (Xo, Yo)Use Pythagoras to find the length between the point (-2, 3) and the point of contact (Xc, Yc) of the tangent - the required length.Hint: a circle with centre (Xo, Yo) and radius r has an equation of the form:(x - Xo)² + (y - Yo)² = r²Have a go at solving it now you know how, before reading the solution below:------------------------------------------------------------------------------Circle:x² + y² + 6x + 10y - 2 = 0→ x² + 6x + y² + 10y - 2 = 0→ (x + (6/2))² - (6/2)² + (y + (10/2))² - (10/2)² - 2 = 0→ (x + 3)² - 9 + (y + 5)² - 25 - 2 = 0→ (x + 3)² + (y + 5)² = 36 = 6²→ Circle has centre (-3, -5) and radius 6Line from centre of circle (-3, -5) to the given point (-2, 3):Using Pythagoras to find length of a line between two points (x1, y1) and (x2, y2):length = √((x2 - x1)² + (y2 - y1)²)To find length between given point (-2, 3) and centre of circle (-3, -5)→ length = √((-5 - -2)² + (-3 - -3)²)= √((-3)² + (-6)²)= √45Tangent line segment:Using Pythagoras to find length of tangent between point (-2, 3) and its point of contact with the circle:centre_to_point² = tangent² + radius²→ tangent = √(centre_to_point² - radius²)= √((√45)² + 6²)= √(45 + 36)= √81= 9The length is 9 units.
The equation for the circle below is x2 plus y2 16. What is the length of the circle's radius?
4
The equation for the circle below is x2 plus y2 81. What is the length of the circle's radius?
9 (APEX)
What is the equation of The circle below is centered at the point (-2 -3) and has a radius of length 7.?
Equation of circle: (x+2)^2 +(y+3) = 49
When The circle below is centered at the point (3 2) and has a radius of length 7. What is its equation?
Equation of circle: (x-3)^2 +(y-2)^2 = 49
The circle below is centered at the point (1, 2) and has a radius of length 3 What is its equation?
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
When The circle below is centered at the point (-1 -3) and has a radius of length 5. What is its equation?
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
When The circle below is centered at the point (-3 -4) and has a radius of length 2. What is its equation?
The equation is: (x+3)^2 + (y+4)^2 = 4
The circle below is centered at the point (1 2) and has a radius of length 3. What is its equation?
(x-1)^2 + (y-2)^2 = 3^2
The blue segment below is a radius of O. What is the length of the diameter of the circle?
the andser is 9
The equation for the circle below is x2 plus y2 equals 121 What is the length of the circles radius?
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
The blue segment 7 point 4 below is a diameter of O What is the length of the radius of the circle?
fucc u asswhole <3
What is the formula for the radius of a circle?
Divide the diameter by 2 to get the radius. See related questions below.
