16 in
16 in*15 in = 240 square inches
If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square
multiply the length by the width by the height
it depends on what shape it is. square: perimenter/4 is one side's length. triangle: perminter/3 rectangle: perimeter/height = length or perimeter/length = height
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
area of rectangle = base x height = 9 x 10 = 90 square cms
A square (a by a) and a rectangle (a by b) can have sides that are of equal length.
Area of a rectangle = length X height = 3*13 = 39 square feet.
The area of rectangle is : 60.0
If you mean a rectangle, just multiply the length times the height. If (for example) length and height are in centimeters, then the area is in square centimeters. Similar for other units.
Rectangle is length times width and triangles are base times height divided by 2.
Area of a rectangle is length x height In this case it is 112 x 30 square mm Do the multiplication and you will have the answer you need
The area of a rectangle is length x width. The area of a triangle is 1/2 base x height. If you mean a rectangle, the area is 70 square units. If you mean a triangle, the area is 35 square units.