16 in
16 in*15 in = 240 square inches
If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square
multiply the length by the width by the height
it depends on what shape it is. square: perimenter/4 is one side's length. triangle: perminter/3 rectangle: perimeter/height = length or perimeter/length = height
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
area of rectangle = base x height = 9 x 10 = 90 square cms
Area of a rectangle = length X height = 3*13 = 39 square feet.
A square (a by a) and a rectangle (a by b) can have sides that are of equal length.
The area of rectangle is : 60.0
If you mean a rectangle, just multiply the length times the height. If (for example) length and height are in centimeters, then the area is in square centimeters. Similar for other units.
Rectangle is length times width and triangles are base times height divided by 2.
Area of a rectangle is length x height In this case it is 112 x 30 square mm Do the multiplication and you will have the answer you need
If the only information that you have is ... A) the figure is a rectangle, and B) the perimeter ... then you cannot calculate the area. The area of a rectangle is the length multiplied by the height., The perimeter is twice the length plus twice the height. So, a rectangle with a length of 9 units and a height of 1 until will have a perimeter of 20 units and an area of 9 square units. Another rectangle with a length of 6 units and a height of 4 units will also have a perimeter of 20 units, but it will have an area of 24 square units. To be able to calculate the area from the perimeter you need to know one of two additional things - either one of the measurements, or the ratio of the height to the length.