From the Pythagorean theorem, the length of the remaining side is the square root of 502 - 302, or the square root of 2500 - 900, or the square root of 1600, or 40m
The area of the triangle in square meters is (1/2 the length of the triangle's base, in meters) times (the length of the triangle's height, in meters).
The length of the hypotenuse if the sides of the right triangle are 6 meters each is: 8.485 meters.
The hypotenuse measures 11.4 meters in length.
That depends entirely on the size of the angles !
It is part of the question itself, 5 metres, one reason being that it is the longest side, and then that sqrt(32 + 42) = 5.
Using Pythagoras' theorem the length of the remaining side is 40 meters
40 metres.
The area of the triangle in square meters is (1/2 the length of the triangle's base, in meters) times (the length of the triangle's height, in meters).
The length of the hypotenuse if the sides of the right triangle are 6 meters each is: 8.485 meters.
8 meters
Assuming that the width of the triangle is the base of the triangle and the the length is height we can calculate area as followed: 1/2 Base x Height = Area of a Triangle (8 meters ÷ 2) x 6 meters = 4 meters x 6 meters = 24 meters².
37 meters
If a right triangle is 12.5 meters and the side opposite a 30 angle, the hypotenuse length will be: 14.43 meters.
Since the area is equal to 1/2 of the product of base and altitude, the base of this triangle must be 4 meters.
There is not enough information to solve this. You need to know one other length od a side to solve this.
9 meters You answered it yourself
Area of a triangle is .5 * b * h, where b is the length of the base and h is the length of the height. Here, the base from which we are measuring the height is 9 meters. So setup the problem:36 m2 = .5 * 9 m * hSolving for h yields 8 meters.