From the Pythagorean theorem, the length of the remaining side is the square root of 502 - 302, or the square root of 2500 - 900, or the square root of 1600, or 40m
The area of the triangle in square meters is (1/2 the length of the triangle's base, in meters) times (the length of the triangle's height, in meters).
The length of the hypotenuse if the sides of the right triangle are 6 meters each is: 8.485 meters.
The hypotenuse measures 11.4 meters in length.
That depends entirely on the size of the angles !
In a right triangle with a 30-degree angle, the length of the side opposite the angle is half the length of the hypotenuse. Therefore, if the side opposite the 30-degree angle is 12.5 meters, the hypotenuse would be 12.5 meters × 2, which equals 25 meters. Rounding to the nearest tenth, the hypotenuse is 25.0 meters.
Using Pythagoras' theorem the length of the remaining side is 40 meters
40 metres.
The area of the triangle in square meters is (1/2 the length of the triangle's base, in meters) times (the length of the triangle's height, in meters).
The length of the hypotenuse if the sides of the right triangle are 6 meters each is: 8.485 meters.
8 meters
Assuming that the width of the triangle is the base of the triangle and the the length is height we can calculate area as followed: 1/2 Base x Height = Area of a Triangle (8 meters ÷ 2) x 6 meters = 4 meters x 6 meters = 24 meters².
37 meters
If a right triangle is 12.5 meters and the side opposite a 30 angle, the hypotenuse length will be: 14.43 meters.
Since the area is equal to 1/2 of the product of base and altitude, the base of this triangle must be 4 meters.
There is not enough information to solve this. You need to know one other length od a side to solve this.
9 meters You answered it yourself
Area of a triangle is .5 * b * h, where b is the length of the base and h is the length of the height. Here, the base from which we are measuring the height is 9 meters. So setup the problem:36 m2 = .5 * 9 m * hSolving for h yields 8 meters.