Area of a triangle is .5 * b * h, where b is the length of the base and h is the length of the height. Here, the base from which we are measuring the height is 9 meters. So setup the problem:
36 m2 = .5 * 9 m * h
Solving for h yields 8 meters.
You do not indicate if the given area is the total area of the square and the triangle. Or whether they are equal values.
The dimensions are: altitude 12 inches and base 7 inches Check: 0.5*12*7 = 42 square inches
The length of each side is seven (7) meters.
The diagonal across a square is one of three legs in a triangle. To determine the length of a leg in a triangle a formula was developed by the ancient Greek mathematician Pythagoras. The "Pythagorean Theorum" [A sq + B sq = C sq]using the two known legs to a triangle [A and B] to determine the third. since the leg [C]. Since we are determining the diagonal across a square we already that [A=6 meters] and [B=6 meters]. So therefore the equation 6 squared [36] + 6 squared [36] = 8.484 squared [72]. So the answer to the diagonal distance across a 6 meter square is; 8.484 meters
Well, darling, to find the length of each side of the square, you simply take the square root of the area. So in this case, the square root of 2.89 square meters is approximately 1.7 meters. So each side of the square would be 1.7 meters in length. Hope that clears things up for you, sugar!
The area of the triangle in square meters is (1/2 the length of the triangle's base, in meters) times (the length of the triangle's height, in meters).
Area of a triangle = (0.5) * (Base) * (Altitude) = (0.5) * (6 meters) * (8 meters) = 24 square meters
It is double the length of the base, in square units.
Area of a triangle = (1/2) (base) (height)= (1/2) (12) (14) = 84 square meters
Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.
It is: 11.5 cm because 0.5*11.5*16 = 92 square cm
To find the altitude or height of an equilateral triangle, take one-half of the length of a side of the triangle and multiple by "square root" of 3. So, if for example, the side has length 10, the height = 5 Square root of 3.
You can find it by using the Pythagorean theorem if you know the side and the base of triangle. In an isosceles triangle the median is also the altitude. The formula is: (The measure of the side length)^2 - (The measure of the one half of the base length )^2 = (The measure of the altitude)^2. Find the square root of the result that you'll have the measure of the altitude.
If you are given the length of 1 leg, L, and the altitude, A, the length of the base is the 2x square root of (L2 -A2 )
Using Pythagoras' theorem it works out as 10.5 units of measurement
Side = 6 cm 1/2 of the base = 3 cm Altitude = 3 times square-root of 3 = 5.196 cm (rounded)
Each side of the square is 3 meters in length