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Area of pipe when thickness of wall inner radius of pipe and length of pipe is given?
For a pipe of uniform radius and thickness, I believe the total surface area would be the Outside surface + Inside surface+ 2 times the surface of the ends. The inside radius(rinner), pipe thickness (t), and pipe length (L) are given.So you only need to find the outside radius (Rout) and then all areas can be calculated.The outside radius should be Rout=rinner +t. And note the perimeter of a circle is 2*pi*Radius and area of an annular region (in this case the ends of the pipe) is A= pi*(Rout2 - rinner2)For the outer pipe surface: Aout=2*pi*(Rout)*LFor the inner pipe surface: Ainner=2*pi*(rinner)*LFor each pipe end: Aend= pi*(Rout2 - rinner2)So the total surface area of the pipe would be: Aout+ Ainner+2* AendOr: Atotal =2*pi*(Rout)*L+2*pi*(rinner)*L+ 2*pi*(Rout2-rinner2)= pi*[ 2*L*(Rout + rinner)]+(Rout2 - rinner2)= 2*pi*[ L*( rinner +t + rinner)]+(( rinner +t )2 - rinner2)]=2*pi*(t+L)(t+2*rinner)Hopefully that is correct and helps.
What is the total surface area of a sphere when the radius is 4?
The total surface area of a sphere when the radius is 4 equals 201.1 units2
If the total area of a cylinder is 90pi and the height is 12 what is the radius?
If the total area of a cylinder is 90pi (282.6) and the height is 12, the radius will be three (3).
How do you find total surface area of a cylinder in terms of radius?
Total surface area including the two end pieces = (2*pi*radius2)+(2*pi*radius*height) in square units.
Total surface area of a cylinder with a height of 8 and a radius of 2?
Total surface area is 176 units2
Is the core 1 percent of the Earth's volume?
No. The combined thickness of the inner and outer core is about 3500 to 3520 kilometers, out of the Earth's total radius of about 6370 kilometers. This means that the combination of inner solid core and liquid outer core has about 16% of the Earth's volume. *The reference to "1% of the Earth's volume" may refer to the Earth's crust, which has about "1% of the Earth's total mass."
What is the same size as the planet Mars?
With a radius of 3396km, the planet Mars is about the same size as the inner and outer core of the earth (which is around 3490km radius in total).
How do you calculate the surface area of a 90 degree elbow?
To calculate the surface area of a 90-degree elbow, you need to consider both the outer and inner surfaces. First, measure the outer radius (R) and inner radius (r) of the elbow, as well as its length (L). The outer surface area can be estimated using the formula for the lateral surface area of a cylindrical section: (A_{outer} = 2\pi R L + 2\pi R^2) (for the two ends). The inner surface area is calculated similarly: (A_{inner} = 2\pi r L + 2\pi r^2). The total surface area is then the sum of both areas.
Is the inner core big?
The inner core has a radius of 1220 kmA extending from the centre of the Earth approximately 6370 km below Earth's surface to 5150 km below the surface (the change from inner to outer core is marked by a density change known as the Lehmann discontinuity). The inner core has a total volume of 7.4207x109 km3.
How wide is the inner core?
Roughly 1216 kilometers.
What is the volume of Earth's ice?
The core consists of an inner solid core with a radius of 760 miles, and an outer liquid core with a total diameter of 1400 miles. Applying the 4/3pi(r3) volume formula to these values we get: 1.8 billion cubic miles for the solid core and 11.7 billion cubic miles for the total outer and inner core volume. This compares to a total volume for the earth of 32.5 billion cubic miles.
It takes ten identical pieces to form a circular track for a pair of toy racing cars If the inside of each piece is 3.4 inches shorter than the outside arc what is the width of the track?
Length of outer track = sum of length of 10 pieces = circumference of the outer circleif R is the Radius of outer circle then...Circumference of the outer track = 2pi*RSimilarly the circumference of the inner track (with radius r) = 2pi*rlength of each outer piece is 3.4 inch more than length of inner pieceSo total outer length is 10*3.4 =34 inches more than the inner length.=> Outer Circumference - Inner Circumference = 34 inches=> 2pi*R - 2pi*r = 34=> 2pi(R -r) = 34=> R-r = 34/2pi = 5.41 inches=> R-r = Width of the track = 5.41 inches1 year ago
How much of the earth is taken up by the inner and outer core?
The Earth's inner and outer core together make up about 15% of the planet's total volume. The outer core is liquid and comprises approximately 55% of this core volume, while the inner core is solid and accounts for the remaining 45%. In terms of mass, the core constitutes about one-third of the Earth's total mass.
How can I count bike chain links accurately?
To count bike chain links accurately, lay the chain flat and count the inner and outer links separately. Each pair of inner and outer links counts as one chain link. Add the total number of inner and outer links to get the accurate count.
A circular magnet has an inner radius of x cm. An outer radius 2cm langer and its depth is the same as the inner radius If the total volume of the magnet is 120π cm3 find x?
The total volume of the magnetic disc (including the central hole) = π(x + 2)² x ; as x + 2 is the outer radius and x is the depth. The volume of the inner "hole" = πx² x. The total volume of the magnet = π(x + 2)² x - πx² x = 120π Dividing by π gives, x³ + 4x² + 4x - x³ = 120 : x² + x = 30 : x² + x - 30 = 0 This can be factored as (x + 6)(x - 5) = 0 As we are only concerned with the positive root then this occurs when x - 5 = 0, then x = 5 NOTE : When x² + x = 30 this could have been written as x(x + 1) = 30 and by inspection the answer 5 x 6 = 30 could be readily deduced, confirming that x = 5.
How do you find the area of a compact disc?
Suppose the diameter of the disk is D cm so that the radius is D/2 = R cm. Suppose the diameter of the hole is d cm so that its radius is d/2 = r cm. Then the area of one side of te disc is pi*(R^2 - r^2) Therefore the total area of the two sides is 2*pi*(R^2 - r^2) square cm. This ignores the surface area of the edge which, although small, is not 0.
How many front wheel bearings need to be replaced on a 1991 Ford Ranger 4x4.Is there 2 or a total of 4 bearings.?
there are a total of 4 wheel bearings on the front both sides have an inner and outer bearing. the outer bearing is visable when you remove hub the inner bearing is visable when you remove rotor
