213
There are seven digits: 8,000,000
00
It is 2.
I'm sure there are more than 2 prime numbers that are 400 digits long.
121
for any composite number ... check only the highest power of prime factors divisibility .... i guess that will do the work for example ... 400 = 2^4 * 5^2 so you need to check the divisibility by 25 as well as 16 hope this will meet your need
you forgot the last 2 digits of your user ID for a games website. You know that both digits are odd. Find the probability that you type the correct last digits by randomly typing 2 odd numbers
The last three digits of 16,123 are "1," "2" and "3," in that order.
213
There are seven digits: 8,000,000
There are 400. Assuming the number must be at least 10,000, then: In a 5 digit palindrome, the first and last digits must be the same, and the second and fourth digits must be the same; and: For the first and last digit there is a choice of 4 digits {2, 4, 6, 8}; For each of these there is a choice of 10 digits {0, 1, ..., 9} for the second and fourth digits; For each of the above choices these is a choice of 10 digits {0, 1, ..., 9} for the third digit; Making 4 x 10 x 10 = 400 possible even 5 digit palindromes.
00
400
It is 2.
This can be solved by looking at each set of digit lengths. From 1 through 9, it's obvious there are 9 digits. From 10 through 99, there are 2 digits for each of the 90 numbers, so that makes 90*2=180 digits. Next, from 100 to 400, there are 401 numbers with 3 digits each, making another 401*3=1,203 digits. So the final answer is 9+180+1,203 = 1,392 digits.
double end digits refers to the last 2 digits of a number e.g the double end digits for 49988227493 is equal to 93.