you forgot the last 2 digits of your user ID for a games website. You know that both digits are odd. Find the probability that you type the correct last digits by randomly typing 2 odd numbers
There is 100% chance.
That depends what rules you use, to choose a number randomly.
None of the digits can be 10, so the probability is 0.
It is possible to create a 3-digit number, without repeated digits so the probability is 1.
Oh, dude, the probability of guessing the last digit of a phone number is 1 in 10, because there are 10 possible digits (0-9). So, like, if you randomly guess, you have a 10% chance of getting it right. But hey, don't stress about it too much, it's just a phone number!
The question is ambiguous. It is in complete.
6561
The answer is 4/9 or 44.444... % Any permutation of the digits 1 to 9 will be divisible by 9. So divisibility by 18 depends only on whether or not the last digit is even. If the last digit is 2, 4, 6 or 8 the number is divisible by 18 and if it is 1, 3, 5, 7 or 9 it is not. So 4 favourable outcomes out of 9 ie probability = 4/9.
The number is 13 digits in length. The first 2 digits = the month of birth; the next 3 digits are randomly assigned; the next 4 digits = the year of birth; the next 2 digits = "41" (it was the 41st state); and the last 2 digits = day of birth.
For a four digit pin number: You receive the first PIN number, let's say WXYZ. The probability that the next pin number you receive would match (assuming they are randomly provided), is: For each digit, they are 10 possibilities [0 1 2 3 4 5 6 7 8 8]. The probability that one specific number is chosen is thus of 1/10. For the are four digits, hence four independent selection of one digit, each with a probability of 1/10. The probability of an event, combination of independent events, is the product of the the probability of the independent event. Thus, the probability that the next pin number you receive would match (assuming they are randomly provided), is: 1/10*1/10*1/10*1/10 or 1/10^4 or 0.0001 or 1 out 10000
49/9000
It is 1. Think of any number between 1 and 10 million.