To determine the number of even 2-digit whole numbers less than 50 using the digits 1-9, we need to consider the possible combinations. The even digits are 2, 4, 6, and 8. For the tens place, we can choose any digit from 1-4 (since we want numbers less than 50). For the units place, we can choose any of the even digits. Therefore, there are 4 choices for the tens place and 4 choices for the units place, resulting in a total of 4 x 4 = 16 even 2-digit whole numbers less than 50 using the digits 1-9.
815*537 = 2.56*1039 in standard form Therefore it will have 40 digits.
72
Production for five people was as follows: 8 units, 11 units, 6 units, 12 units, 8 units. What was their average production in units?
987 7 raised to the power of 8 raised to the power of 9. This equals7.0316765e+60 !!
To find the units digit of 8 to the power of 50, we need to look for a pattern in the units digits of powers of 8. The units digit of powers of 8 cycles in a pattern: 8^1 = 8, 8^2 = 4, 8^3 = 2, 8^4 = 6, and so on. Since the cycle repeats every 4 powers, we can divide 50 by 4 to find that the 50th power will have the same units digit as 8^2, which is 4. Therefore, the units digit of 8 to the power of 50 is 4.
To find the units digit of a number raised to a power, we can look for patterns in the units digits of the powers of that number. For 2, the units digits of the powers cycle in a pattern: 2, 4, 8, 6. Since 2011 is 3 more than a multiple of 4 (2011 = 4 * 502 + 3), the units digit of 2 to the power of 2011 will be the fourth number in the cycle, which is 6.
The units digits start with 8 and go down in steps of 2. The units digit repeats every 5 multiples, The last pair of digits repeat every 25 multiples.
When the units digit equals the tens digit then the sum of the digits of a 2 digit number is double the units digit. In each tens range above 50, numbers below this critical point meet the requirement, numbers above this critical point have a sum LESS than double the units digit. The applicable numbers are 51-54 (4), 61-65 (5), 71-76 (6), 81-87 (7) and 91-98 (8). Then there are 4 + 5 + 6 + 7 + 8 = 30 qualifying numbers.
Integers divisible by 8 have their last 3 digits divisible by 8. So: 2934829387957008 is divisible by 8 because the last three digits are divisible by 8 (008 / 8 = 1). 2348012934801298304400 is also (400 / 8 = 50). 123006 is not (006 / 8 = 0.75).
For you A+ Cheaters ;D it's 50!
819 = 144115188075855872 The number in the units column is therefore 2.
815*537 = 2.56*1039 in standard form Therefore it will have 40 digits.
72
8 to the 5th power
If we add 51 and 17 (51 + 17), we'd get 68 for an answer. The number 51 is 50 + 1, and the number 17 is 10 + 7, taking the units digits, 1 + 7 equals 8, and 50 + 10 equals 60. Further, 8 plus 60 is 68, so the sum of 51 and 17 is 68.
Using 3.14 as Pi the area of circle is: 0