Let the length be (2x+3) and the width be be x:
length*width = area
(2x+3)*x = 93 sq cm
2x2+3x-93 = 0
Solving the above quadratic equation gives a positive value for x as 6.110211367
Therefore: width = 6.110 cm to 3 decimal places
Check: (2*6.110211367+3)*(6.110211367) = 93 sq cm
The length is (18 centimeters) minus (the width)
3 cm
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
77cm!
30 ft
The length is (18 centimeters) minus (the width)
21cm3
3 cm
150 cm !
46 centimeters
In a rectangle, the area is calculated by multiplying length x width. If (for example) both length and width are in centimeters, the area will be in square centimeters.
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
77cm!
The width of the rectangle is 4 cm
9 cm