Best Answer

Let the length be (2x+3) and the width be be x:

length*width = area

(2x+3)*x = 93 sq cm

2x2+3x-93 = 0

Solving the above quadratic equation gives a positive value for x as 6.110211367

Therefore: width = 6.110 cm to 3 decimal places

Check: (2*6.110211367+3)*(6.110211367) = 93 sq cm

Q: The length of a rectangle is 3 cm more than 2 times its width If the area of the rectangle is 93 square centimeters find the width of the rectangle to the nearest thousandth?

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The length is (18 centimeters) minus (the width)

3 cm

Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter

the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle

77cm!

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In a rectangle, the area is calculated by multiplying length x width. If (for example) both length and width are in centimeters, the area will be in square centimeters.

Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter

the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle

77cm!

The width of the rectangle is 4 cm

To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.