In a rectangle, the area is calculated by multiplying length x width. If (for example) both length and width are in centimeters, the area will be in square centimeters.
P = 46 cm A = 120 sq cm
It's half the area of a rectangle
Area of a rectangle = length x width
Area of a rectangle: a = l * w
Area of a square/rectangle=its length × its width
If it is a rectangle and not a square there is not enough information to solve this problem for area. Perimeter is 2( B+H) = 46 Area = BH
No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
P = 46 cm A = 120 sq cm
Make it 2 wide and 21 long and you've got it.
Perimeter is the length of a closed line around an area. A rectangle is an area. If each long side of the rectangle is 12 cm and each end of the rectangle is 9 cm, the total length is 14+14+9+9 or 46 cm.
A rectangle which is 46 feet by 34 feet would have two sides of length 46 and two sides of length 34. Add these together to get the total length needed to enclose the area. (46+46+34+34)ft = 160ft
Rectangle area = (rectangle width) x (rectangle height)
A = lw Area of a rectangle = length times width
11 x 12 rectangle has a larger perimeter = 46 units The 132 square unit area will give a square a perimeter of 45.9565 units
The area of rectangle is : 35.0
It's half the area of a rectangle
The area of rectangle is : 48.0