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Designate the length and width in meters by l and w respectively. Then, ,from the problem statement, l = 6 + 2w and l X w = 140. Substituting the first of these equations into the second yields w(6 + 2w) = 140, or, rearranging into standard form, 2w2 + 6w - 140 = 0; dividing by 2 gives w2 + 3 w - 70 = 0. This can be factored into (w-7)(w+10) = 0, which is true for either w = -10 or w = 7. A real rectangle, however, can not have a negative width; therefore, w = 7 and l = 20.

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Q: The length of a rectangle is 6 meters more than twice the with If the area of the rectangle is 140 square meters find the dimensions?
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