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First, let's call the length of the rectangle L, and the width W.

We know that the length is 8 more than the width, i.e

L = W+8

Now we also know that the perimeter of a rectangle is P=2L+2W, where the P in this case is would be 24.

Which gives us 2 equations;

L = W+8 [1]

24=2L+2W [2]

Using simultaneous equations, lets find the perimeter in terms of W, by substituting in the value of L in equation [1]

24 = 2(W+8)+2W

Expand:

24 = 2W+16+2W

Simplify:

4W + 16 = 24

Subtract 16 from both sides:

4W = 8

W = 2

Now substitute W=2 into [1]:

L = 2+8

L = 10

Therefore:

The length and width of the rectangle are 10 units and 2 units respectively.

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Q: The length of a rectangle is 8 in more than its widthThe permiter of the rectangle is 24 inWhat sre the width and length of the rectangle?
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