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The length of a rectangle is 8 in more than its widthThe permiter of the rectangle is 24 inWhat sre the width and length of the rectangle?
First, let's call the length of the rectangle L, and the width W.
We know that the length is 8 more than the width, i.e
L = W+8
Now we also know that the perimeter of a rectangle is P=2L+2W, where the P in this case is would be 24.
Which gives us 2 equations;
L = W+8 [1]
24=2L+2W [2]
Using simultaneous equations, lets find the perimeter in terms of W, by substituting in the value of L in equation [1]
24 = 2(W+8)+2W
Expand:
24 = 2W+16+2W
Simplify:
4W + 16 = 24
Subtract 16 from both sides:
4W = 8
W = 2
Now substitute W=2 into [1]:
L = 2+8
L = 10
Therefore:
The length and width of the rectangle are 10 units and 2 units respectively.
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