The rectangle is 23cm x 16cm
Half the perimeter is 78 / 2= 39cm (which is one side and one end).
39 - 7 = 32cm
32 / 2 = 16cm (one end)
16 + 7 = 23cm (one side)
Proof:
(23 + 16) x 2 = 78cm the perimeter.
The perimeter of a rectangle is 2 x length + 2 x width. If the width is 16 then 78 = 2 x length + 2 x 16 2 x length = 78 - 32 = 46 length = 23. For the perimeter to be greater than 78 cm, the length must be greater than 23 cm
Since the perimeter equals the two lengths added to the two widths you can write this equation since you know the actual perimeter.78cm = 2l + 2wSince the area is the length multiplied by the width you can write this equation since you know the actual area.108= lwYou have two variables (length and width) that you do not know. Sinceyou have two equations you can solve for the variables. you can use substitution or addition ifyou would like. I will use substitution.l=108/w78=2(108/w) + 2w78=216/w + 2w78w = 216 + 2w20 = 2w2 -78w + 216w = 3cm or 36cmnow put both into the equations to find the length (l)78 = 2l + 2(3 or 36)78 = 2l + 6 or 722l = 72 or 6l = 3cm or 36cmYour dimensions are 36cm X 3cm
a metre=100 cm half a metre=(.5)*(100)=50 cm total length=previous length+half a length = 78 cm +50 cm =128 cm or 1.28 metre
1m 78cm = 5' 10.1"
1cm = 10mm so 780mm = 780/10 = 78cm
The perimeter of a rectangle is 2 x length + 2 x width. If the width is 16 then 78 = 2 x length + 2 x 16 2 x length = 78 - 32 = 46 length = 23. For the perimeter to be greater than 78 cm, the length must be greater than 23 cm
Perimeter = 2 x Length + 2 x Width = 78 cm ie P = 2L + 2W = 78 L = W + 7 so 2W + 14 + 2W = 78 so 4W = 64 so W = 16 L = W + 7 = 16 + 7 = 23 Length= 23 cm Width= 16 cm
Since the perimeter equals the two lengths added to the two widths you can write this equation since you know the actual perimeter.78cm = 2l + 2wSince the area is the length multiplied by the width you can write this equation since you know the actual area.108= lwYou have two variables (length and width) that you do not know. Sinceyou have two equations you can solve for the variables. you can use substitution or addition ifyou would like. I will use substitution.l=108/w78=2(108/w) + 2w78=216/w + 2w78w = 216 + 2w20 = 2w2 -78w + 216w = 3cm or 36cmnow put both into the equations to find the length (l)78 = 2l + 2(3 or 36)78 = 2l + 6 or 722l = 72 or 6l = 3cm or 36cmYour dimensions are 36cm X 3cm
13 by 6
a metre=100 cm half a metre=(.5)*(100)=50 cm total length=previous length+half a length = 78 cm +50 cm =128 cm or 1.28 metre
since one inch approximately equals to 2.54cm, therefore 78cm is app. equal to 30.708 inches
1 metre 78cm
6 metres and 78cm
78 centimeters is 0.78 meter.
1m 78cm
1m 78cm = 5' 10.1"
78cm is approximately 2 feet 6¾ inches.