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If your question states 230cm squared instead of cubed the answer is: length=X; width=x-1; area=230=x(x-1)=x2-x; per Bhaskara's quadratic equation
x=(-b+-(b2-4ac)(1/2))/2a
x=(1+-(1-4(-230))(1/2))/2
x=(1+-(921(1/2)))/2
x=(1+30.34798)/2
x aprox=15.67399=lenght => width aprox=14.67399 => area=230

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Q: The length of this rectangle is 1cm more than its width it has an area of 230cm cubed what is the answer?
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