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The length of this rectangle is 1cm more than its width it has an area of 230cm cubed what is the answer?
If your question states 230cm squared instead of cubed the answer is: length=X; width=x-1; area=230=x(x-1)=x2-x; per Bhaskara's quadratic equation
x=(-b+-(b2-4ac)(1/2))/2a
x=(1+-(1-4(-230))(1/2))/2
x=(1+-(921(1/2)))/2
x=(1+30.34798)/2
x aprox=15.67399=lenght => width aprox=14.67399 => area=230
What else can I help you with?
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To find the height, we can use the formula for the volume of a rectangular prism, which is length x width x height. Rearranging the formula, we have height = volume / (length x width). Substituting the given values, the height of the rectangle prism would be 120 in cubed / (4in x 6in) = 5 in.
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A rectangle with width 4 can have any length!
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The width and length of a rectangle are two of its main dimensions. The width is the measurement of the shorter side of the rectangle, while the length is the measurement of the longer side. The area of a rectangle is calculated by multiplying the width by the length.
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A rectangle with width 4 can have any length!
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