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The measure of angle abd 9x 7 and the measure of angle dca 11x - 3 find the measure of angle dca?
Sandyht43
The question cannot be answered with no information on what the angles refer to nor what the overall shape is!
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Find the measure of angle abd if the measure of angle dbc is 16 degrees and the measure of angle abc is 89 degrees?
The measurement of angle ABD is 73 degrees. You find this angle by subtracting angle DBC from angle ABC, or 89-16 is equal to 73 degrees.
DC equals 1O What is the measure of angle ABD?
if DC = 10 What is the measure of angle ABD?
Ray bd bisects angle abc find the value of x if the measure of angle abd is represented by 7x plus 8 and the measure of angle dbc is represented by 9x-2?
5
Ray BD bisects angle ABC. The measure of angle ABD is represented by 4x-4 and the measure of angle ABC is represented by 7x plus 4. Find the measures of angle DBC.?
Angle ABD = 4x - 4 Angle ABC = twice angle ABD = 7x + 4 So 7x + 4 = 2*(4x - 4) = 8x - 8 So x = 12 Then angle DBC = half of angle ABC = 1/2*(7*12 + 4) = 1/2*88 = 44 degrees.
What is the measure of angle ABD?
that purely depends on the given polygon and any information about it
What is the measure of x if the measure of angle abd is represented by 2x the measure of angle dbc is represented by 5x and the measure of angle abc is 91 degrees?
The answer is 13. x=13 13*5+13*2=91 Thank you.
If angle abd is 110 and angle cbd is 60 then what is angle abc?
50
How do i prove if the base angles of a triangle are congruent then the triangle is isosceles?
Suppose you have triangle ABC with base BC, and angle B = angle C. Draw the altitude AD.Considers triangles ABD and ACDangle ABD = angle ACD (given)angle ADB = 90 deg = angle ACDtherefore angle BAD = angle CADAlso the side AD is common to the two triangles.Therefore triangle ABD is congruent to triangle ACD (ASA) and so AB = AC.That is, triangle ABC is isosceles.
What is the proof that equiangular triangle is also called equilateral triangle?
Label the triangle ABC. Draw the bisector of angle A to meet BC at D. Then in triangles ABD and ACD, angle ABD = angle ACD (equiangular triangle) angle BAD = angle CAD (AD is angle bisector) so angle ADB = angle ACD (third angle of triangles). Also AD is common. So, by ASA, triangle ABD is congruent to triangle ACD and therefore AB = AC. By drawing the bisector of angle B, it can be shown that AB = BC. Therefore, AB = BC = AC ie the triangle is equilateral.
How do you prove that the diagonals in a rhombus divide the rhombus into four congruent triangles?
The proof is fairly long but relatively straightforward. You may find it easier to follow if you have a diagram: unfortunately, the support for graphics on this browser are hopelessly inadequate.Suppose you have a rhombus ABCD so that AB = BC = CD = DA. Also AB DC and AD BC.Suppose the diagonals of the rhombus meet at P.Now AB DC and BD is an intercept. Then angle ABD = angle BDC.Also, in triangle ABD, AB = AD. therefore angle ABD = angle ADC.while in triangle BCD, BC = CD so that angle DBC = angle BDC.Similarly, it can be shown that angle BAC = angle CAD = angle DCA = angle ACB.Now consider triangles ABP and CBP. angle ABP (ABD) = angle CBP ( CBD or DBC),sides AB = BCand angle BAP (BAC) = angle BCP (BCA = ACB).Therefore, by SAS, the two triangles are congruent.In the same way, triangles BCP and CPD can be shown to congruent as can triangles CPD and DPA. That is, all four triangles are congruent.
In the figure below ABD measures 37. What is the measure of ABC?
74 deegrees
When ab is perpendicular to CD?
when angle abc and abd equalls to 90 degree then ab perpendicular to cd
