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Suppose you have triangle ABC with base BC, and angle B = angle C. Draw the altitude AD.

Considers triangles ABD and ACD

angle ABD = angle ACD (given)

angle ADB = 90 deg = angle ACD

therefore angle BAD = angle CAD

Also the side AD is common to the two triangles.

Therefore triangle ABD is congruent to triangle ACD (ASA) and so AB = AC.

That is, triangle ABC is isosceles.


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Q: How do i prove if the base angles of a triangle are congruent then the triangle is isosceles?
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